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anyanavicka [17]
2 years ago
7

Parabola with focus (2, 1) and directrix x=-8

Mathematics
1 answer:
scoray [572]2 years ago
6 0

Consider we need to find the equation of the parabola.

Given:

Parabola with focus (2, 1) and directrix x=-8.

To find:

The equation of the parabola.

Solution:

We have directrix x=-8. so, it is a horizontal parabola.

The equation of a horizontal parabola is

(y-k)^2=4p(x-h)           ...(i)

where, (h,k) is center, (h+p,k) is focus and x=h-p is directrix.

On comparing focus, we get

(h+p,k)=(2,1)

h+p=2          ...(ii)

k=1

On comparing directrix, we get

h-p=-8         ...(iii)

Adding (ii) and (iii), we get

2h=2+(-8)

2h=-6

Divide both sides by 2.

h=-3

Putting h=-3 in (ii), we get

-3+p=2

p=2+3

p=5

Putting h=-3, k=1 and p=5 in (i), we get

(y-1)^2=4(5)(x-(-3))

(y-1)^2=20(x+3)

Therefore, the equation of the parabola is (y-1)^2=20(x+3).

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