Answer: $122.50
<u>Step-by-step explanation:</u>
In Out
8:00 12:00 = 4 hours
12:45 17:30 =<u> 4.75 hours </u>
Total 8.75 hours
8.75 hours x $14/hr = $122.50
Note: to subtract 12:45 from 17:30, borrow 1 hour from 17 and add 60 minutes to 30:
17:30 → 16:90
- 12:45 -<u> 12:45 </u>
4: 45
4 hours 45 minutes =
= 4.75 hours
Answer:
3y=x-1 OR y=⅓x-⅓
Step-by-step explanation:
Lets call the equation y=-3x+7 line l1
the other line passing through (4,1) l2
If two lines are perpendicular,then the product of their roots=-1
That is m(l1)×m(l2)=-1
Slope of l1=-3 therefore slope of l2=-1÷-3=⅓
Now that we have determined the slope of l2 we move on to find it's equation using the point-slope form
y-y1=m(x-x1)
y-1=⅓(x-4)
3y-3=x-4
3y=x-4+3
3y=x-1 OR y=⅓x-⅓
Answer:
Step-by-step explanation:
Hello!
X: number of absences per tutorial per student over the past 5 years(percentage)
X≈N(μ;σ²)
You have to construct a 90% to estimate the population mean of the percentage of absences per tutorial of the students over the past 5 years.
The formula for the CI is:
X[bar] ±
* 
⇒ The population standard deviation is unknown and since the distribution is approximate, I'll use the estimation of the standard deviation in place of the population parameter.
Number of Absences 13.9 16.4 12.3 13.2 8.4 4.4 10.3 8.8 4.8 10.9 15.9 9.7 4.5 11.5 5.7 10.8 9.7 8.2 10.3 12.2 10.6 16.2 15.2 1.7 11.7 11.9 10.0 12.4
X[bar]= 10.41
S= 3.71

[10.41±1.645*
]
[9.26; 11.56]
Using a confidence level of 90% you'd expect that the interval [9.26; 11.56]% contains the value of the population mean of the percentage of absences per tutorial of the students over the past 5 years.
I hope this helps!
Answer:
In some circumstances these displays may allow the female to observe the performance of males and to evaluate them as potential mates. To elicit displays from a group of males, a female Mallard may swim with her neck outstretched and her head just above the water
Step-by-step explanation:
hope this helps
A radioactive atmosphere around the area and an expensive, hard time cleaning everything up.