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noname [10]
3 years ago
7

Heeeeeeeeeeeeelp meeeeeeeeeeeeeeeee

Mathematics
2 answers:
Valentin [98]3 years ago
8 0

Answer:

7

Step-by-step explanation:

You have to multiply all of them with 8

AlexFokin [52]3 years ago
7 0
The answer is 7 because you are dividing the output to the input you will get 8 for each so therefore you divide 56 by 8 to get 7
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Please help for 18 n 19
Hitman42 [59]
18. \ \ \frac{-1}{x-9}- \frac{-2}{x+7}= \frac{-1(x+7)+2(x-9)}{(x-9)(x+7)}= \frac{-x-7+2x-18}{(x-9)(x+7)}= \frac{x-25}{(x-9)(x+7)}


\frac{2}{x}+ \frac{12}{x}=7 \\    \\  \frac{14}{x} =7 \\  \\ x= \frac{14}{7} \\  \\ x=2
7 0
3 years ago
The first side of a triangle is 4m shorter than the second side. The third side 3 times as long as the first side. The perimeter
viktelen [127]

Answer:

1st side= 4m

2nd side= 8m

3rd side= 12m

Step-by-step explanation:

Let the first, second and third side of the triangle be a, b and c meters respectively.

a= b -4 -----(1)

c= 3a -----(2)

Perimeter of triangle

= a +b +c

= 24

a +b +c= 24 -----(3)

From (1): b= a +4 -----(4)

Subst. (2) and (4) into (3):

a +(a +4) +3a= 24

3a +a +a +4= 24

5a +4= 24

5a= 24 -4

5a= 20

Divide both sides by 5:

a= 20 ÷5

a= 4

Substitute a= 4 into (4):

b= 4 +4

b= 8

Substitute a= 4 into (2):

c= 3(4)

c= 12

Thus, the lengths of the first, second, and third side of the triangle are 4m, 8m and 12m respectively.

4 0
3 years ago
the first term of a arithmetic sequence is 2 and the 4th term is 11, how do I find the sum of the first 50 terms
Rama09 [41]
\bf n^{th}\textit{ term of an arithmetic sequence}\\\\
a_n=a_1+(n-1)d\qquad 
\begin{cases}
n=n^{th}\ term\\
a_1=\textit{first term's value}\\
d=\textit{common difference}\\
----------\\
a_1=2\\
a_4=11\\
n=4
\end{cases}
\\\\\\
a_4=2+(4-1)d\implies 11=2+(4-1)d\implies 11=2+3d
\\\\\\
9=3d\implies \cfrac{9}{3}=d\implies \boxed{3=d}\\\\
-------------------------------\\\\

\bf \textit{now, what's the 50th term anyway?}
\\\\\\
n^{th}\textit{ term of an arithmetic sequence}\\\\
a_n=a_1+(n-1)d\qquad 
\begin{cases}
n=n^{th}\ term\\
a_1=\textit{first term's value}\\
d=\textit{common difference}\\
----------\\
a_1=2\\
n=50\\
d=3
\end{cases}
\\\\\\
a_{50}=2+(50-1)3\implies a_{50}=2+147\implies a_{50}=149\\\\
-------------------------------\\\\

\bf \textit{sum of a finite arithmetic sequence}\\\\
S_n=\cfrac{n}{2}(a_1+a_n)\quad 
\begin{cases}
n=50\\
a_1=2\\
a_{50}=149
\end{cases}\implies S_{50}=\cfrac{50}{2}(2+149)
7 0
4 years ago
Simplify.<br>2x – 15 + 3x – 33 - 10​
solong [7]

Answer:

5x - 58

Step-by-step explanation:

6 0
3 years ago
Read 2 more answers
Pls help quick
Inga [223]
For the second one, $5.00 is the change
7 0
3 years ago
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