Answer:
Reactive power is 1.152 VARs
Step-by-step explanation:
We are given that in a parallel circuit,
,R=47kΩ and 
=50kΩ.
reactive power means the dissipating power resulting from inductive and capacitive loads measured in volt-amperes reactive(VAR).Since our circuit has inductor only, reactive power will be power dissipated from inductor.
Current through inductor=
milli amps=0.0048 A
Reactive power = (current flowing through inductor)X (Voltage across inductor)
Hence reactive power = 0.0048 X 240=1.152 VARs
The answer is y = -2/3x -2
Just have to Subtract two on both sides the. Divide all numbers by 3
Could you please mark me brainleist
Answer:
the function represnted in the table is linear
Step-by-step explanation:
Okay so for number one you use PEMDAS so you can either divide 144 by 12 first or multiply 5 and 6 or divide 6 by 3.
Normally, I do multiplicarion first so the first step would be to multiply 5 and 6 with is 30 so the new equation is 144/12+30/3 okay and then do the divisions.
So the new equation would be 12+10 and which equals 22
And for number two since you have a variable you can't use PEMDAS so just distribute the 11 but only to the ones in the parentheses.
So the new equation turns out to be 11x-33+5=0
Okay then, since you need to figure out what x is, you move over -33 and 5 by adding 33 and subtracting 5 which gives you 11x=33-5
And then just solve 11x=28 and x is a decimal number. (x=2.55)
It made me laugh i like it
