Using the z-distribution, the 99% confidence interval to estimate the population proportion is: (0.2364, 0.4836).
<h3>What is a confidence interval of proportions?</h3>
A confidence interval of proportions is given by:
In which:
- is the sample proportion.
In this problem, we have a 99% confidence level, hence, z is the value of Z that has a p-value of , so the critical value is z = 2.575.
The estimate and the sample size are given by:
.
Then the bounds of the interval are:
The 99% confidence interval to estimate the population proportion is: (0.2364, 0.4836).
More can be learned about the z-distribution at brainly.com/question/25890103
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Answer:
Her monthly salary is $4395.83
Step-by-step explanation:
Annual = 12 months
12 months = $52 750
1 month = $52 750 ÷ 12
= $4395.83(2d.p)
Monthly = $4395.83
(Correct me if i am wrong)
square root of (9-6)^2 +(5-1)^2 = 5
the distance is 5 units
Answer: 1. B 10(15 12 + 8) = 350
2. C
Step-by-step explanation: