Question

The sum of five consecutive positive integers is 2020. Find the largets of these numbers.

Answer 1

Answer:

406

Step-by-step explanation:

let the 5 consecutive positive integers be

n , n + 1 , n + 2 , n + 3 , n + 4 , then

n + n + 1 + n + 2 + n + 3 + n + 4 = 2020

5n + 10 = 2020 ( subtract 10 from both sides )

5n = 2010 ( divide both sides by 5 )

n = 402

then

largest integer = n + 4 = 402 + 4 = 406