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IRINA_888 [86]
3 years ago
15

I'll give brainliest your options are:a. 60b. 120c. 180d. 40​

Mathematics
1 answer:
Lapatulllka [165]3 years ago
3 0

Answer:

the answer is A

Step-by-step explanation:

It is an acute angle but is larger than 40

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Vanessa wants to purchase a new cell phone plan. The two plans from which she can choose are shown below. Vanessa used the syste
user100 [1]

Answer:

2. 325 minutes.

Step by step explanation:

We will substitute our given number of minutes in our both equation one by one to find the correct option.

1. Let us substitute m= 775 in both equations.

CA=22+0.13m

CA=22+0.13\cdot 775

CA=22+100.75=122.75

CB=44+0.09(m-100)

CB=44+0.09(775-100)    

CB=44+0.09\cdot675

CB=44+60.75=104.75

104.75\neq122.75

We can see that both plans have different costs , therefore, 1st option is incorrect.

2. Let us substitute m= 325 in both equations.

CA=22+0.13m

CA=22+0.13\cdot 325

CA=22+42.25=64.25

CB=44+0.09(m-100)

CB=44+0.09(325-100)

CB=44+0.09\cdot 225

CB=44+20.25=64.25

64.25=64.25

When Vanessa has used the phone for 325 minutes, the cost for Plan A and the cost for Plan B will both be $64.25.Therefore, 2nd option is correct choice.

3. Let us substitute m= 32.5 in both equations.

CA=22+0.13m

CA=22+0.13\cdot 32.5

CA=22+4.225=26.225

CB=44+0.09(m-100)

CB=44+0.09(32.5-100)

CB=44+0.09\cdot -67.5

CB=44-6.075=37.925    

37.925\neq26.225

4. Let us substitute m= 764 in both equations.

CA=22+0.13m

CA=22+0.13\cdot 764

CA=22+99.32=121.32

CB=44+0.09(m-100)

CB=44+0.09(764-100)

CB=44+0.09\cdot 664

CB=44+59.76=103.76  

121.32\neq103.76

Therefore, 4th option is incorrect.




3 0
4 years ago
I'd really appreciate it if you'd help! :)
sergij07 [2.7K]

The answer to your question is

h=2y+36

why?

because he was already 36 inches which mean he would be adding on the inches.

So he would grow 2 inches a year plus the 36 inches he already was.


Hope this helps

5 0
3 years ago
What are the domain and range of f(x)-[x-2] +1
svetlana [45]
Replace <span><span>f<span>(x)</span></span><span>f<span>(x)</span></span></span> with <span>yy</span>.<span><span>y=<span>x2</span>−1</span><span>y=<span>x2</span>-1

</span></span>Interchange the variables.<span><span>x=<span>y2</span>−1</span><span>x=<span>y2</span>-1

</span></span>Solve for <span>yy</span>.
<span><span>y=<span>√<span>1+x</span></span>,−<span>√<span>1+x</span></span></span><span>y=<span>1+x</span>,-<span>1+x

</span></span></span>Solve for <span>yy</span> and replace with <span><span><span>f<span>−1</span></span><span>(x)</span></span><span><span>f<span>-1</span></span><span>(x)</span></span></span>.
<span><span><span>This is your answer=f<span>−1</span></span><span>(x)</span>=<span>√<span>1+x</span></span>,−<span>√<span>1+x</span></span></span><span><span>f<span>-1</span></span><span>(x)</span>=<span>1+x</span>,-<span>1+x
Hope you have a wonderful day! hope this helps!



</span></span></span>
7 0
3 years ago
Brianna's chocolate chip cookie recipe will make about 3 dozen chocolate chip cookies the recipe calls for 2 1/4 cups of flour a
coldgirl [10]
Write and solve an equation of ratios to answer this.

2.25 cup              x
-------------- = -------------
0.375 cup          1 cup
                                                                                  2.25
cross-multiplying, 2.25 = 0.375x.  Solving for x, x = ---------- = 6
                                                                                   0.375

Brianna would need to use 6 cups of flour if she wants the mixture to contain 1 cup of baking soda.

6 0
3 years ago
Read 2 more answers
Machine M, working alone at its constant rate, produces x widgets every 4 minutes. Machine N, working alone at its constant rate
Harman [31]

Answer:

Yes

Step-by-step explanation:

Given that Machine M, working alone at its constant rate, produces x widgets every 4 minutes. Machine N, working alone at its constant rate, produces y widgets every 5 minutes.

When both machines work for 20 minutes

Machine A would produce = \frac{20}{4} =5 widget and

Machine B would produce = \frac{20}{5} =4 widgets

So we can say that Machine A would produce more widgets than Machine N at that time.

Answer is Yes

8 0
3 years ago
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