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Deffense [45]
3 years ago
11

Which of the following statements have the same result? Explain each step in solving each one.

Mathematics
1 answer:
rjkz [21]3 years ago
7 0

Answer:

None of the following statements have the same result.

Step-by-step explanation:

1) f(2) when f(x) = 3x + 4

We just have to put x=2

f(x)=3x+4\\f(2)=3(2)+4\\f(2)=6+4\\f(2)=10

So, f(2) when f(x) = 3x + 4 is x=10

2) f⁻¹ (4)  when f(x) =3x-4/5

We need to find f⁻¹(x) first.

Put y=3x-\frac{4}{5}

Now solve for x

Add 4/5 on both sides

y+\frac{4}{5}=3x-\frac{4}{5}\\y+\frac{4}{5}=3x\\x=\frac{1}{3}y+\frac{4}{5*3}\\x=\frac{1}{3}y+\frac{4}{15}\\x=\frac{5y+4}{15}

Now put  f⁻¹(x)  instead of x and replace y with x

f^{-1}(x)=\frac{5x+4}{15}

Now finding f⁻¹(4)

f^{-1}(x)=\frac{5x+4}{15} \\f^{-1}(4)=\frac{5(4)+4}{15} \\f^{-1}(4)=\frac{20+4}{15} \\f^{-1}(4)=\frac{24}{15}

f⁻¹ (4)  when f(x) =3x-4/5 is 24/15

3) 3y - 6 = y + 10\\

Solving:

3y - 6 = y + 10\\3y-y=10+6\\2y=16\\y=16/2\\y=8

Solving 3y − 6 = y + 10, we get y=8

None of the following statements have the same result.

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Answer:

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Hope this helps :)

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