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2 years ago

A professional football field is 160 feet wide. What is the width in yards?

Mathematics

2 answers:

nirvana33 [79]2 years ago

5 0

can you tell me what the area is?

a_sh-v [17]2 years ago

3 0

One yard is three feet.
160 feet is 160/3 yards. = 53 yards and one foot.

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2−2n=3n+17 whats the solution

Kazeer [188]

2-2n=3n+17
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3 years ago

A kite has side lengths of 2 feet and 4 feet. Each side length is increased by the same number of feet. The expression represent

inysia [295]

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Which algebraic expression represents “the difference of fifty-four and seven times a number”? 54 minus 7 n StartFraction 54 Ove

VMariaS [17]

Answer: 54-7n

Step-by-step explanation:

When we talk about mathematical language, the difference between two numbers, quantities or terms is the substraction operation.

For example, the difference between a and b is:

a-b

On the other hand, if we read a numer c times a number n, this means both numbers are multiplied.

For example:

c times n is:

(c)(n)

So, according to the explained above, “the difference of fifty-four and seven times a number n” is:

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2 years ago

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Write each expression as an algebraic (nontrigonometric) expression in u, u > 0.

max2010maxim [7]

Answer:

$\displaystyle \sin\left(2\sec^{-1}\left(\frac{u}{10}\right)\right)=\frac{20\sqrt{u^2-100}}{u^2}\text{ where } u>0$

Step-by-step explanation:

We want to write the trignometric expression:

$\displaystyle \sin\left(2\sec^{-1}\left(\frac{u}{10}\right)\right)\text{ where } u>0$

As an algebraic equation.

First, we can focus on the inner expression. Let θ equal the expression:

$\displaystyle \theta=\sec^{-1}\left(\frac{u}{10}\right)$

Take the secant of both sides:

$\displaystyle \sec(\theta)=\frac{u}{10}$

Since secant is the ratio of the hypotenuse side to the adjacent side, this means that the opposite side is:

$\displaystyle o=\sqrt{u^2-10^2}=\sqrt{u^2-100}$

By substitutition:

$\displaystyle= \sin(2\theta)$

Using an double-angle identity:

$=2\sin(\theta)\cos(\theta)$

We know that the opposite side is √(u² -100), the adjacent side is 10, and the hypotenuse is u. Therefore:

$\displaystyle =2\left(\frac{\sqrt{u^2-100}}{u}\right)\left(\frac{10}{u}\right)$

Simplify. Therefore:

$\displaystyle \sin\left(2\sec^{-1}\left(\frac{u}{10}\right)\right)=\frac{20\sqrt{u^2-100}}{u^2}\text{ where } u>0$

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2 years ago

Michael played a game of darts. He threw 14 darts and hit the target

solniwko [45]

3/7

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1 year ago