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dangina [55]
3 years ago
13

Plz help me... it would help if u did all the questions :)

Mathematics
2 answers:
LekaFEV [45]3 years ago
8 0

Answer:

i dont see a x-

Step-by-step explanation:

Sergio039 [100]3 years ago
7 0
5x and 85 are VERTICAL
5x and 5y are ADJACENT
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What is this please help
Olegator [25]

Answer: The answer in the blank is 2/5.

Step-by-step explanation: To divide fractions, flip the second fraction's denominator and nominator and then change the sign to a multiplication sign. Multiply. 4/5 x 3/1 = 12/5. Make 12/5 a mixed number. Since 12 can hold 2 fives, the people who created this question placed a 2 before the blank. 2/5 is remaining, so the blank is 2/5.

8 0
2 years ago
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You worked 9 hours. how many of those hours were overtime hours?
fredd [130]

Answer:

4? Is this even a questions? I think people work 3-7 hours a day at a normal office job...

Step-by-step explanation:


6 0
2 years ago
Which factors can be multiplied together to make the trinomial 5x2 + 8x – 4? Check all that apply. (x + 1) (2x + 1) (x + 2) (5x
andreyandreev [35.5K]

Answer:

(5x-2) and (x+2)

Step-by-step explanation:


8 0
2 years ago
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Given that 18f = 33g, identify the ratio off to g in simplest form.
Kobotan [32]

Answer:

11/6

Step-by-step explanation:

18f = 33g

f/g = 33/18 = 11/6

8 0
2 years ago
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rock is thrown upward with a velocity of 27 meters per second from the top of a 23 meter high cliff and it misses the cliff on t
ahrayia [7]

the rock will be at 11 meters from the ground level after 5.92 seconds

Step-by-step explanation:

The motion of the rock is a free-fall motion, since the rock is acted upon the force of gravity only. Therefore, it is a uniformly accelerated motion, so its position at time t is given by the equation:

y=h+ut+\frac{1}{2}at^2

where

h = 23 m is the initial height

u = 27 m/s is the initial velocity, upward

a=g=-9.8 m/s^2 is the acceleration of gravity, downward

t is the time

We want to find the time t at which the position of the rock is

y = 11 m

Substituting and re-arranging the equation, we find

11=23+27t-4.9t^2\\4.9t^2-27t-12=0

This is a second-order equation, which has solutions:

t=\frac{27\pm \sqrt{(-27)^2-4(4.9)(-12)}}{2(4.9)}=\frac{27\pm \sqrt{964.2}}{9.8}

So

t_1 = -0.41 s

t_2=5.92 s

The first solution is negative so we neglect it: therefore, the rock will be at 11 meters from the ground level after 5.92 seconds.

Learn more about free fall:

brainly.com/question/1748290

brainly.com/question/11042118

brainly.com/question/2455974

brainly.com/question/2607086

#LearnwithBrainly

8 0
3 years ago
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