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Citrus2011 [14]
2 years ago
7

Help plsssssssssss i really need help

Mathematics
2 answers:
MakcuM [25]2 years ago
4 0

Answer:

part A = 256

part B = 8

part C =2

Step-by-step explanation:

=)have good day

mariarad [96]2 years ago
3 0

Answer:

A= 256 stickers   B= 8 stickers per student  C= 1 more box

Step-by-step explanation:

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Im pretty sure it's false because 7.4p could 74, 148, 222 or 296. so it would be the other way around. It's false.

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A class has 6 boys and 15 girls. what is the ratio of boys to girls
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egoroff_w [7]

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10x=4

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Step-by-step explanation:

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3 years ago
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If you roll two fair dice repeatedly, what is the probability that you will get a sum of 4 before you get a sum of 5 ? (a) (b) (
AlexFokin [52]

Answer:

The probability that you will get a sum of 4 before you get a sum of 5 is \frac{1}{12}

Step-by-step explanation:

Given : If you roll two fair dice repeatedly.

To find : What is the probability that you will get a sum of 4 before you get a sum of 5 ?

Solution :

When two dice are rolled the outcomes are

(1,1) (1,2) (1,3) (1,4) (1,5) (1,6)

(2,1) (2,2) (2,3) (2,4) (2,5) (2,6)

(3,1) (3,2) (3,3) (3,4) (3,5) (3,6)

(4,1) (4,2) (4,3) (4,4) (4,5) (4,6)

(5,1) (5,2) (5,3) (5,4) (5,5) (5,6)

(6,1) (6,2) (6,3) (6,4) (6,5) (6,6)

Total number of outcomes = 36

Favorable outcome get a sum of 4 before you get a sum of 5 is (1,3) ,(2,2) and (3,1) = 3

The probability that you will get a sum of 4 before you get a sum of 5 is

P=\frac{3}{36}

P=\frac{1}{12}

Therefore, The probability that you will get a sum of 4 before you get a sum of 5 is \frac{1}{12}

5 0
3 years ago
Answer Is not C<br>please help​
Katyanochek1 [597]

Answer:

B

Step-by-step explanation:

Well since it is arthimetic sequence we know the formula

We know d is difference between second term and first so it will be -5- (-12)= -5+12= 7

a_{n}= a _{1}+ d (n-1) \\a_{n}= -12+7(n-1)\\a_{n} = -12+7n-7\\a_{n}= 7n-19

the domain of this is 1,2,3,4.......

range is -12,-5,2,9.......

Therefore answer is B.

5 0
3 years ago
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