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Alja [10]
3 years ago
6

A jar contains 12 red marbles numbered 1 to 12 and 10 blue marbles numbered 1 to 10. A marble is drawn at random from the jar. F

ind the probability of the given event. (a) The marble is red
Mathematics
1 answer:
klasskru [66]3 years ago
8 0

Answer:

<h2>6/11</h2>

Step-by-step explanation:

Step one:

given data

sample space

red marbles= 12

blue marbles= 10

sample size= 12+10

sample size= 22

Step two:

Required

Find the probability of the given event. (a) The marble is red

Let the probabiilty be P(R)

P(R)= 12/22

P(R)= 6/11

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Given:
μ = 200 lb, the mean
σ = 25, the standard deviation

For the random variable x = 250 lb, the z-score is
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From standard tables for the normal distribution, obtain
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4 years ago
Which method is not used to find the solution of a system of linear equations. guess and checkA. graphingB. substitutionC. matri
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Answer:

guess and check

Step-by-step explanation:

Linear equation systems usually have two or more variables to find.

The values for these variables can be found by different methods, some of them are indeed graphing, substitution and with matrices.

So these are correct options that are used to solve linear systems of equations.

On the other hand, the guess and check method is not used to find the solution of these systems, since the more variables the system has the more difficult it is to guess the answer,<u> the graphic and mathematical methods are more effective and reliable.</u>

6 0
3 years ago
A car has a windshield wiper on the driver's side that has total arm length of 10 inches. It rotates
son4ous [18]

Answer:

75.44 Square Inches

Step-by-step explanation:

The diagram of the problem is produced and attached.

To determine the area of the cleaned sector:

Let the radius of the larger sector be R

Let the radius of the smaller sector be r

Area of the larger sector =\frac{\theta}{360}X\pi R^2

Area of the smaller sector =\frac{\theta}{360}X\pi r^2

Area of shaded part =Area of the larger sector-Area of the smaller sector

=\frac{\theta}{360}X\pi R^2-\frac{\theta}{360}X\pi r^2\\=\frac{\theta \pi}{360}X (R^2- r^2)

From the diagram, R=10 Inch, r=10-7=3 Inch, \theta=95^\circ

Therefore, Area of the sector cleaned

=\frac{95 \pi}{360}X (10^2- 3^2)\\=75.44$ Square Inches

7 0
3 years ago
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