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meriva
3 years ago
9

Six cakes cost £2.40 how much do ten cakes cost

Mathematics
2 answers:
aivan3 [116]3 years ago
6 0
Divide 2.40 by 6 than multiply your answer by 10. 

total = 4.00 dollars
Stells [14]3 years ago
4 0
There are a few ways to find out the correct answer. One of them is to divide 2.40 by 6 to get a price of one cake and then multiply it by 10:

2.40 ÷ 6 = 0.40
0.40 * 10 = 4.00

Ten cakes would cost 4 pounds.
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Determine whether the events are independent (I) or dependent (D). Place your answer in the blank provided. 1. Ramiro draws a ma
Stels [109]

Answer:

Independent events

Step-by-step explanation:

Given that:

Ramiro draws a marble from a jar without replacement and then flips a coin

Let E_1 be the event that Ramiro draws a marble without replacement and;

Let E_2 be the event of flipping a coin.

Let's have an analogy so that we can better understand the concept of independent and dependent events.

Consider a random experiment in which a marble is drawn from a jar without replacement and a fair coin is flipped together.

The event E_1  does not in any way affect the event E_2  of a head or a tail showing up in  a flip of a coin.

Therefore, we say that E_1  and E_2   are independent events.

Suppose the event  E_1  affects or influence the event E_2  , then we can say they are dependent events.

4 0
4 years ago
Find rate of change help show work.
sukhopar [10]

Answer:

rise/run = 2/-4 or it is rise/run = -2/4

3 0
2 years ago
What is the nearest ten thousand rounded to 836527
motikmotik

Answer:

837,000

Step-by-step explanation:

If a number is above 5 round up, if it is below 4 round down

3 0
4 years ago
Read 2 more answers
On a trip, a motorist drove 150 miles in the morning and 50 miles in the afternoon. His average rate in the morning was twice hi
Lina20 [59]

Answer:

Morning's average rate = 50 mph, and Afternoon's average rate = 25 mph.

Step-by-step explanation:

Suppose he drove 150 miles for X hours, then his average rate in the morning was (150/X) mph.

Given that he spent 5 hours in driving.

And he drove 50 miles for (5-X) hours, then his average rate in the afternoon was 50/(5-X) mph.

Given that his average rate in the morning was twice his average rate in the afternoon.

(150/x) = 2 * 50/(5-x)

150/x = 100/(5-x)

Cross multiplying terms, we get:-

150*(5-x) = 100*x

750 - 150x = 100x

750 = 100x + 150x

750 = 250x

x = 750/250 = 3.

It means he spent 3 hours in the morning and 2 hours in the afternoon.

So morning's average rate = 150/3 = 50 mph.

and afternoon's average rate = 50/(5-3) = 25 mph.

8 0
3 years ago
Is the confidence interval affected by the fact that the data appear to be from a population that is not normally​ distributed?
sp2606 [1]

Answer:

D. No, because the sample size is large enough.

Step-by-step explanation:

The central limit theorem states that "if we have a population with mean μ and standard deviation σ and take sufficiently large random samples from the population with replacement, then the distribution of the sample means will be approximately normally distributed. This will hold true regardless of whether the source population is normal or skewed, provided the sample size is sufficiently large".

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

If the sample size is higher than 30, on this case the answer would be:

D. No, because the sample size is large enough.

And the reason is given by The Central Limit Theorem since states if the individual distribution is normal then the sampling distribution for the sample mean is also normal.

From the central limit theorem we know that the distribution for the sample mean \bar X is given by:

\bar X \sim N(\mu, \frac{\sigma}{\sqrt{n}})

If the sample size it's not large enough n<30, on that case the distribution would be not normal.

7 0
3 years ago
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