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Ivenika [448]
3 years ago
11

Thanks for you help btw thanks​

Mathematics
2 answers:
Snezhnost [94]3 years ago
8 0

Answer:

parralel lines

Step-by-step explanation:

you're very welcome

yan [13]3 years ago
4 0
<h2>Answer:</h2><h2>They are parralel lines.</h2>
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Which table represents the statement “A freight train is traveling at an average rate of 45 miles per hour”?
LUCKY_DIMON [66]

Answer:

The third one i think

Step-by-step explanation:

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0.2(3b - 15c) <br> plz help me
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Answer:

if you meant to simplify here you go

Step-by-step explanation:

0.2(3b - 15c)=

0.2(3b)+0.2(−15c)=

0.6b−3c

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Rahm spent 2 1\2 hoirs writing a n essay. it took hime 4 times as long to finish his science project. how long did it take him t
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Answer: it took him 12 1/2 hours to complete both projects.

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You are studying the water properties of a bog in eastern Wisconsin and wish to estimate its acidity. You de ne a grid that cove
GenaCL600 [577]

Answer:

4.8-1.453\frac{1.3}{\sqrt{82}}=4.591    

4.8+1.453\frac{1.3}{\sqrt{82}}=5.009    

So on this case the 85% confidence interval would be given by (4.591;5.009)    

And we can conclude that the true mean for the acidity at 85% of confidence is between  (4.591;5.009)    

Step-by-step explanation:

Previous concepts

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".

The margin of error is the range of values below and above the sample statistic in a confidence interval.

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

\bar X represent the sample mean for the sample  

\mu population mean (variable of interest)

s represent the sample standard deviation

n represent the sample size  

Solution to the problem

The confidence interval for the mean is given by the following formula:

\bar X \pm t_{\alpha/2}\frac{s}{\sqrt{n}}   (1)

In order to calculate the critical value t_{\alpha/2} we need to find first the degrees of freedom, given by:

df=n-1=82-1=81

Since the Confidence is 0.85 or 85%, the value of \alpha=0.15 and \alpha/2 =0.075, and we can use excel, a calculator or a table to find the critical value. The excel command would be: "=-T.INV(0.075,81)".And we see that t_{\alpha/2}=1.453

Now we have everything in order to replace into formula (1):

4.8-1.453\frac{1.3}{\sqrt{82}}=4.591    

4.8+1.453\frac{1.3}{\sqrt{82}}=5.009    

So on this case the 85% confidence interval would be given by (4.591;5.009)    

And we can conclude that the true mean for the acidity at 85% of confidence is between  (4.591;5.009)    

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Square root of 342354456​
-Dominant- [34]

Answer:

18502.8229198

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