Answer:
Width=13cm
Length=18cm
Step-by-step explanation:
Width of the Initial Photograph=9cm
Length of the Initial Photograph=14cm
If width and length are increased by an equal amount, say x
New Width=9+x
New Length=14+x
Area of the new photo is 108 square centimeters greater than the area of the original photo.
Area of Original Photo=14*9=126cm²
Aeea of the New Photo=126+108=234cm²
Therefore:
(9+x)(14+x)=234
126+9x+14x+x²-234=0
x²+23x-108=0
x²+27x-4x-108=0
x(x+27)-4(x+27)=0
(x+27)(x-4)=0
x+27=0 or x-4=0
x=-27 or x=4
Since x≠-27
x=4cm
The dimensions of the new photo are:
Width=9+x=9+4=13cm
Length=14+x=14+4=18cm
Boom here u go the answer is 13.3922
Differentiate:x^2 + y^2 = 4
You get this:2x + 2yy' = 0
bring the x variable on the other side:2yy' = -2x
Now divide 2y to leave y' by itself:y' = -2x/2y
Answer: y' = -x/y
The given relation is not a implicit solution to the given differential equation.
a ) The domain:
x^4 - 16 x² ≥ 0
x² ( x² - 16 ) ≥ 0
x² - 16 ≥ 0
x² ≥ 16
x ∈ ( - ∞, - 4 ] ∪ [ 4 , + ∞ )b ) f ` ( x ) =
=
( 2 x³ - 16 x ) / √(x^4 - 16 x²)c ) The slope of the tangent line at x = 5:
f ` ( 5 ) = ( 2 * 125 - 16 * 5 ) / √ ( 625 - 400 ) = 170 / 15 = 34 / 3
The slope of the line normal to the graph at x = 5:
m = - 3 / 34
To do it without a calculator:
10% of 67 is 6.7
6.7 x 8 is 53.6 (80%)
1% of 67 is .67
<span>53.6 - .67 is 52.93 (79%)</span>
