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nataly862011 [7]
3 years ago
11

Solve for C = 2pie.

Mathematics
1 answer:
bonufazy [111]3 years ago
5 0
I don’t think you can do that
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Find the indefinite integral. (remember to use absolute values where appropriate. use c for the constant of integration.) x2 − 2
julsineya [31]
:) Well, I dunno about anyone else but this question makes my head spin!

6 0
3 years ago
A car travels 26 miles on 1 gallon of gas. Jorge drives 130 miles and uses 5 gallons of gas.
bogdanovich [222]

Answer:

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Step-by-step explanation:

6 0
2 years ago
For the function y=3x2: (a) Find the average rate of change of y with respect to x over the interval [3,6]. (b) Find the instant
nirvana33 [79]

Answer:

The instantaneous rate of change of y with respect to x at the value x = 3 is 18.

Step-by-step explanation:

a) Geometrically speaking, the average rate of change of y with respect to x over the interval by definition of secant line:

r = \frac{y(b) -y(a)}{b-a} (1)

Where:

a, b - Lower and upper bounds of the interval.

y(a), y(b) - Function exaluated at lower and upper bounds of the interval.

If we know that y = 3\cdot x^{2}, a = 3 and b = 6, then the average rate of change of y with respect to x over the interval is:

r = \frac{3\cdot (6)^{2}-3\cdot (3)^{2}}{6-3}

r = 27

The average rate of change of y with respect to x over the interval [3,6] is 27.

b) The instantaneous rate of change can be determined by the following definition:

y' =  \lim_{h \to 0}\frac{y(x+h)-y(x)}{h} (2)

Where:

h - Change rate.

y(x), y(x+h) - Function evaluated at x and x+h.

If we know that x = 3 and y = 3\cdot x^{2}, then the instantaneous rate of change of y with respect to x is:

y' =  \lim_{h \to 0} \frac{3\cdot (x+h)^{2}-3\cdot x^{2}}{h}

y' =  3\cdot \lim_{h \to 0} \frac{(x+h)^{2}-x^{2}}{h}

y' = 3\cdot  \lim_{h \to 0} \frac{2\cdot h\cdot x +h^{2}}{h}

y' = 6\cdot  \lim_{h \to 0} x +3\cdot  \lim_{h \to 0} h

y' = 6\cdot x

y' = 6\cdot (3)

y' = 18

The instantaneous rate of change of y with respect to x at the value x = 3 is 18.

5 0
3 years ago
Pls help, its probs gonna get deleted
Paladinen [302]

Sorry it took so long :)

3 0
3 years ago
<img src="https://tex.z-dn.net/?f=%5Csqrt%7B%5Cfrac%7B36%7D%7B169%7D%7D" id="TexFormula1" title="\sqrt{\frac{36}{169}}" alt="\sq
otez555 [7]

Answer:

0.0355029585799?

Step-by-step explanation:

5 0
3 years ago
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