I think it would be 21 points total for 7 correct awnsers I did the math hope it helps
Let the lengths of the sides of the rectangle be x and y. Then A(Area) = xy and 2(x+y)=300. You can use substitution to make one equation that gives A in terms of either x or y instead of both.
2(x+y) = 300
x+y = 150
y = 150-x
A=x(150-x) <--(substitution)
The resulting equation is a quadratic equation that is concave down, so it has an absolute maximum. The x value of this maximum is going to be halfway between the zeroes of the function. The zeroes of the function can be found by setting A equal to 0:
0=x(150-x)
x=0, 150
So halfway between the zeroes is 75. Plug this into the quadratic equation to find the maximum area.
A=75(150-75)
A=75*75
A=5625
So the maximum area that can be enclosed is 5625 square feet.
Answer:
46,350
Step-by-step explanation:
3% of 45,000 is 1,350
So, 45,000 + 1350 = 46,350
Answer:
System of equations:
3.5c + 5a = 377
c + a = 85
Solved:
(53, 32)
Step-by-step explanation:
32 children's tickets were sold and 53 adults tickets were sold.
Your answer will be is :
![\mathfrak{3\sqrt[3]{3}}](https://tex.z-dn.net/?f=%5Cmathfrak%7B3%5Csqrt%5B3%5D%7B3%7D%7D)
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EXPLANATION :</u></h2>
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Because its the square root of ![\mathfrak{3\sqrt[3]{3.}}](https://tex.z-dn.net/?f=%5Cmathfrak%7B3%5Csqrt%5B3%5D%7B3.%7D%7D)
Hope It Helps ! ~
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