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WARRIOR [948]
3 years ago
6

ANSWER QUICK AND CORRECTLY AND I WILL MARK THE BRAINLIEST PLEASE HELP!!!!

Mathematics
1 answer:
ahrayia [7]3 years ago
6 0

Answer:

c

Step-by-step explanation:

because I'm brainlyiest

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Please help me!!!!!!!!!
serious [3.7K]
Download the app photomath it will  help you 
6 0
2 years ago
Find the degree of the polynomial: a^3+3a^2−5a
emmainna [20.7K]

Answer:

The degree of the polynomial is 3

Step-by-step explanation:

Given:

a^3+3a^2-5a

To Find:

The degree of the polynomial= ?

Solution:

The degree of the polynomial   is the value of the greatest exponent of any expression (except the constant ) in the polynomial. To find the degree all that you have to do is find the largest exponent in the polynomial

Here in the given polynomial

a^3+3a^2- 5a

The terms are

a^3

3a^2

5a

The term  a^3 has  the largest exponent of  3

Note:  The degree of the polynomial does not depend  on coefficients of the terms

3 0
3 years ago
Y varies directly as x . If y is 2 when x is 8, then the constant of variation is 1/4 . True or False
dedylja [7]

When y = 2, x = 8.

This can be written as: 2/8.

Simplified: 1/4

True


3 0
3 years ago
Read 2 more answers
What is the answer for x+b over 4
Lady_Fox [76]
X/4 + b/4
i need some values tho
8 0
3 years ago
Emily drew a scale drawing of a house and its lot. The back patio is 42 millimeters long in the drawing. The actual patio is 27
kirill [66]

the scale factor used in Emily scale drawing is K = 1.63 mm/m

<h3>What scale did Emily use?</h3>

We know that Emily drew a scale drawing of a house and its lot.

In the scale drawing, the back patio is 42 millimeters long, and we know that the actual patio is 27 meters long.

Then the scale relates the measures 44mm and 27 meters, such that if the scale is K, we can write:

K*27m = 44mm

Solving for K, we can write:

K = (44/27) mm/m = 1.63 mm/m

So the scale factor used in Emily's scale drawing is K = 1.63 mm/m

If you want to learn more about scale factors:

brainly.com/question/25722260

#SPJ1

5 0
2 years ago
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