4 years ago

Please help me with this problem

Mathematics

2 answers:

jolli1 [7]4 years ago

7 0

Answer:

. maybe not..

Step-by-step explanation:

ira [324]4 years ago

5 0

Answer:

B- -2/3 is to the right of -0. 6.

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251 is the smallest whole number

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Step-by-step explanation:

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3 years ago

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3 years ago

The mass, m grams, of a radioactive substance, present at time t days after first being observed, is given by the formula m=24e^

Reika [66]

Answer:

(i) The value of m when t = 30 is 13.2

(ii) The value of t when the mass is half of its value at t=0 is 34.7

(iii) The rate of the mass when t=50 is -0.18

Step-by-step explanation:

(i) The m value when t = 30 is:

$m = 24e^{-0.02t} = 24e^{-0.02*30} = 13.2$

Then, the value of m when t = 30 is 13.2

(ii) The value of the mass when t=0 is:

$m_{0} = 24e^{-0.02t} = 24e^{-0.02*0} = 24$

Now, the value of t is:

$ln(\frac{m_{0}/2}{24}) = -0.02t$

$t = -\frac{ln(\frac{24}{2*24})}{0.02} = 34.7$

Hence, the value of t when the mass is half of its value at t=0 is 34.7

(iii) Finally, the rate at which the mass is decreasing when t=50 is:

$\frac{dm}{dt} = \frac{d}{dt}(24e^{-0.02t}) = 24(e^{-0.02t})*(-0.02) = -0.48* (e^{-0.02*50}) = -0.18$

Therefore, the rate of the mass when t=50 is -0.18.

I hope it helps you!

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3 years ago