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o-na [289]
3 years ago
13

If tanA+cotA=2 then find the value of cosA​

Mathematics
1 answer:
aniked [119]3 years ago
4 0

Answer:

cos A=

\frac{1}{ \sqrt{2} }

Step-by-step explanation:

We know,

cotA=

\frac{1}{ \tan(a) }

Substituting the value of cot A in the given equation, we get

\tan( a)  +  \frac{1}{ \tan(a) }  = 2

\frac{{ \tan }^{2} a + 1}{  \:  \tan(a)  }  = 2

{ \tan }^{2 \: } a \:  + 1 = 2 tan \: a

{ \tan }^{2} a - 2 \tan \: a + 1 = 0

( \tan \: a - 1) {}^{2 }  = 0

\tan \: a - 1 =  \sqrt{0}

\tan \: a = 1

\tan \: a \:  =  \tan \: 45

a = 45

\cos \: a =  \cos \: 45

\cos \: a =   \frac{1}{ \sqrt{2} }

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3 years ago
Ms Bonilla is saving for a vacation she currently has 150 in her savings account and plans to add $25 to the account each week .
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Answer and Step-by-step explanation:

Alright, so when creating any type of math problem, it is important to identify the parts of the problem and where they go. First, we need to start by putting the problem together. We will use one of the most common forms of equations of math, also known as the linear equation of <em>y=mx+b.</em>

So we have: S(w)=__x + __. S(w) is also equal to f(x), which is also equal to y. So: y= __x + __.

Let's start filling this equation in. So, because it says that she will <em>add 25 dollars each week</em>, The problem is addition. Also, the 25 dollars each week will represent the mx in this situation. Here's why:

The x in this can stand for the amount of week she added this 25 dollars to her account. So:

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Now, we can add the 150 to the problem because that is what she started with for this one-time deal. So now we have:

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You can now where everything is represented, but we are not done. Let's change y and x back into S(w) and w like the question asks us to have. So:

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If you want to solve this question, just replace the number of weeks in place of all w's in the equation, like this: S(2)= 25(2) + 150.

I hope that this helps.

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HELLLPPP Multiply. Write your answer in scientific notation. 6 (2 x 10^)(1 x 10​
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Answer:

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I hope I helped you^_^

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