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3 years ago

2

Mathematics

1 answer:

nadezda [96]3 years ago

4 0

Answer:

Area = 559.17 sq ft

Step-by-step explanation:

Area (rectangle) = 18 x 24 = 432

Area (semi-circle = πr²÷2 = 81π/2 = 127.17

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6 2/3 - 2 1/2 please help thanks!!!!!

Fed [463]

The answer would be 6 4/6 - 2 3/6 which would equal 3 1/6.

4 0

4 years ago

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Express 0.96 as an percent

enyata [817]

Answer:

96%

Step-by-step explanation:

0.96 × 100/100

(0.96 × 100)× 1/100 = 96/100

percentage = 96%

6 0

3 years ago

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What are the x and y intercepts of the line described by this equation? 4x-3y=12.3

Nataly [62]

X-intercept is when y=0;

4x-3(0)=12.3
4x=12.3
x=12.3/4
x=3.075 (x-intercept)

y-intercept is when x=0

4(0)-3y=12.3
-3y=12.3
y=12.3/-3
y=-4.1 (y-intercept)

Hope I helped :)

6 0

3 years ago

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Daija wants trim 3.5centimetes from her hair how should she move the decimal point to convert this number to millimeters

cestrela7 [59]

9514 1404 393

Answer:

right

Step-by-step explanation:

1.0 cm = 10. mm . . . . . . the decimal point is moved to the right

3.5 cm = 35. mm . . . . . . the decimal point is moved to the right

5 0

3 years ago

I tell you these facts about a mystery number, $c$: $\bullet$ $1.5 < c < 2$ $\bullet$ $c$ can be written as a fraction wit

makkiz [27]

Answer:

Possible answer: $\displaystyle c = \frac{16}{10} = \frac{8}{5} = 1.6$ .

Step-by-step explanation:

Rewrite the bounds of $c$ as fractions:

The simplest fraction for $1.5$ is $\displaystyle \frac{3}{2}$ . Write the upper bound $2$ as a fraction with the same denominator:

$\displaystyle 2 = 2 \times 1 = 2 \times \frac{2}{2} = \frac{4}{2}$ .

Hence the range for $c$ would be:

$\displaystyle \frac{3}{2} < c < \frac{4}{2}$ .

If the denominator of $c$ is also $2$ , then the range for its numerator (call it $p$ ) would be $3 < p < 4$ . Apparently, no whole number could fit into this interval. The reason is that the interval is open, and the difference between the bounds is less than $2$ .

To solve this problem, consider scaling up the denominator. To make sure that the numerator of the bounds are still whole numbers, multiply both the numerator and the denominator by a whole number (for example, 2.)

$\displaystyle \frac{3}{2} = \frac{2 \times 3}{2 \times 2} = \frac{6}{4}$ .

$\displaystyle \frac{4}{2} = \frac{2\times 4}{2 \times 2} = \frac{8}{4}$ .

At this point, the difference between the numerators is now $2$ . That allows a number ( $7$ in this case) to fit between the bounds. However, $\displaystyle \frac{1}{c} = \frac{4}{7}$ can't be written as finite decimals.

Try multiplying the numerator and the denominator by a different number.

$\displaystyle \frac{3}{2} = \frac{3 \times 3}{3 \times 2} = \frac{9}{6}$ .

$\displaystyle \frac{4}{2} = \frac{3\times 4}{3 \times 2} = \frac{12}{6}$ .

$\displaystyle \frac{3}{2} = \frac{4 \times 3}{4 \times 2} = \frac{12}{8}$ .

$\displaystyle \frac{4}{2} = \frac{4\times 4}{4 \times 2} = \frac{16}{8}$ .

$\displaystyle \frac{3}{2} = \frac{5 \times 3}{5 \times 2} = \frac{15}{10}$ .

$\displaystyle \frac{4}{2} = \frac{5\times 4}{5 \times 2} = \frac{20}{10}$ .

It is important to note that some expressions for $c$ can be simplified. For example, $\displaystyle \frac{16}{10} = \frac{2 \times 8}{2 \times 5} = \frac{8}{5}$ because of the common factor $2$ .

Apparently $\displaystyle c = \frac{16}{10} = \frac{8}{5}$ works. $c = 1.6$ while $\displaystyle \frac{1}{c} = \frac{5}{8} = 0.625$ .

8 0

4 years ago

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