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3 years ago

8

the monthly revenue for printer ink for a large office supply store is r(x) =-x^2 +12x+13, where x is the price of an ink cartri

dge in dollars and r(x) is in hundreds of dollars. what is the maximum monthly ink revenue

1 answer:

steposvetlana [31]3 years ago

4 0

Answer:

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Step-by-step explanation:

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Simplify using the order of operations.<br> 9−4 ·5+6

Aleksandr-060686 [28]

we know that the multiplication comes first in the family then we start from left to right

4 x 5= 20

9-20 = -11

-11 + 6 = -5

there you go!

3 0

2 years ago

Read 2 more answers

A garrison of 400men had food for 40days.After 10 days,200 more men joined them .How long will the food last now?(Assume that th

mestny [16]

Let $x$ be the amount of food needed for one man for one day. At the beginning, we have enough food for 400 men for 40 days, i.e.

$400\cdot 40\cdot x = 16000x$

After 10 days, the 400 men will have consumed

$400\cdot 10\cdot x = 4000x$

food, impliying that the food remaining is

$16000x-4000x=12000x$

If 200 more men join the garrison, there are now 600 men. Each of them requires $x$ food each day, and there are $12000x$ units of food remaining. They will last

$\dfrac{12000x}{600}=20$ days.

6 0

3 years ago

Before a bag of flour can be sold, it must be 40 kilograms but can be within 0.5

Serjik [45]

Answer:

The minimum acceptable weight of the flour bag is 39.5 kg,

and its maximum acceptable weight is 40.5 kg

Step-by-step explanation:

Notice that the selling weight of the bag to be sold (x) needs to differ from 40 kg at most 0.5 kg. Therefore, we can write the following inequality:

$|x-40|\leq 0.5$

The inequality can be solve once we remove the absolute value symbol, and solve for the unknown "x". Recall that in order to solve it, we need to consider the two possible cases:

a) that the expression within the absolute value symbol is larger than or equal to zero, and b) that the expression is less than zero.

a) If $x-40\geq 0$ then its absolute value is equal to itself (x-40), and when we remove the absolute value symbols, we get:

$x-40\leq 0.5\\x\leq 0.5+40\\x\leq 40.5\,\,kg$

which means that the weigh "x" of the flour bag should be smaller or equal than 40.5 kg

b) If $x-40$ , then the absolute value of this is its opposite : -x+40, and the inequality becomes:

$-x+40\leq 0.5\\40\leq 0.5+x\\40-0.5\leq x\\39.5\leq x$

which means that the weight of the flour bag must be larger than or equal to 39.5 kg

So, the minimum acceptable weight of the flour bag is 39.5 kg, and the maximum acceptable weight is 40.5 kg

6 0

3 years ago

Help fast!! (no links please.)

amid [387]

Answer:

C) 3

Step-by-step explanation:

Plug in the values on c and d and solve

((3)^2 + (2)^2) - 2((3)^2 - (2)^2)

Solve inside the parenthesis first

(9+4) - 2(9-4) = (13) - 2(5)

Distribute the 2 and solve

13 - 10 = 3

4 0

2 years ago

If on the unit circle C, the distance from P(1, 0) to the point T ( 4/5 , 3/5 ) is x, determine the coordinates of the point at

AveGali [126]

Answer:

$(\frac{4}{5}, -\frac{3}{5} )$

Step-by-step explanation:

The point P(1,0) and T $(\frac{4}{5}, \frac{3}{5} )$ are on the unit circle C and the arc length from P to T is x.

Let us assume that point P - x i.e. the point obtained by moving clock wise direction along the circle from P is T'.

Because of the symmetry of the circle about the coordinate axes, the x-coordinate of point T' will be $\frac{4}{5}$ and the y-coordinate will be $-\frac{3}{5}$ .

So, coordinates of T' are $(\frac{4}{5}, -\frac{3}{5} )$ .

Here we must notice that point T' is the reflection point of T with respect to X-axis. (Answer)

3 0

3 years ago