Answer:
No
Step-by-step explanation:
For a point to be the midpoint of a line segment, it must bisect it into two equal segments and be on the line segment (hence, colinear with the endpoints). All four B points are equidistant from points A and C, but aren’t colinear with A and C. Therefore, they aren’t all midpoints of line segment AC.
I hope this helps! :)
Answer:
-1/3
Step-by-step explanation:
3 is the gradient of the other line
m1×m2=-1 (equation for perpendicular lines)
m1×3= -1
m1= -1/3
Pls confirm if its correct
correct me if wrong
thanks! :)
<h3>
Answer: -7 < x < 17</h3>
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Explanation:
Plug in the lower bound of the domain, which is x = -3
f(x) = 3x+2
f(-3) = 3(-3)+2
f(-3) = -9+2
f(-3) = -7
If x = -3, then the output is y = -7. Since f(x) is an increasing function (due to the positive slope), we know that y = -7 is the lower bound of the range.
If you plugged in x = 5, you should find that f(5) = 17 making this the upper bound of the range.
The range of f(x) is -7 < y < 17
Recall that the domain and range swap places when going from the original function f(x) to the inverse 
This swap happens because how x and y change places when determining the inverse itself. In other words, you go from y = 3x+2 to x = 3y+2. Solving for y gets us y = (x-2)/3 which is the inverse.
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In short, we found the range of f(x) is -7 < y < 17.
That means the domain of the inverse is -7 < x < 17 since the domain and range swap roles when going from original to inverse.
If the dimensions are "nice" factors of the quadratic, and if y > -3, we have
.. area = (y +3)(y +5)
y+5 is greater than y +3, so we take the width to be ....
.. width = y+3