Answer: 
This translates to "y is any real number such that it is 0 or larger".
The reasoning is that the result of any absolute value function is either 0 or positive. In other words, we'll never get a negative result of an absolute value function. This is due to how absolute value represents distance. Negative distance does not make sense.
So if y = |x-3| then y = 0 is the smallest output possible. We could have any positive output we want.
In terms of a graph (see below), the V shape is at the lowest point (3,0). The y coordinate is all we care about in terms of finding the range. So we see the lowest y value is y = 0.
(3x2 + 9x + 6) − (8x2 + 3x − 10) + (2x + 4)(3x − 7)
First distribute the (2x+4)(3x-7) to get 6x2-2x-28
After this just add the like terms for all parts of the expression.
(3x2-8x2+6x2)+(9x-3x-2x)+(6+10-28)
x2+4x-12
So you answer is x2+4x-12
Answer:
15
Step-by-step explanation: