Answer:
1/4 hopefully this helps you with work
Answer: 0.000007638035
Step-by-step explanation:
We can use the formula for compound interest to solve this.
Now, the formula goes thus:
A = P ( 1 + r/n)^nt
Where A is the amount compounded, P is the initial amount I.e the principal, r is the rate in % , t is the time while n is the number of times the interest is compounded per time I.e how many times per year.
From the question, we get the following parameters, A = $1912.41 , P = ? , t = 15 years, r = 2.63% and n = 1 of course.
Now, we substitute these into the formula
1912.41 = P ( 1 + 2.63) ^ 15
1912.41 = P ( 3.63) ^ 15
1912.41 = P ( 250,379,850)
P = 1912.41 ÷ 250,379,850
P = 0.000007638035
Looks pretty funny an answer right?
Answer: the probability that a measurement exceeds 13 milliamperes is 0.067
Step-by-step explanation:
Suppose that the current measurements in a strip of wire are assumed to follow a normal distribution, we would apply the formula for normal distribution which is expressed as
z = (x - µ)/σ
Where
x = current measurements in a strip.
µ = mean current
σ = standard deviation
From the information given,
µ = 10
σ = 2
We want to find the probability that a measurement exceeds 13 milliamperes. It is expressed as
P(x > 13) = 1 - P(x ≤ 13)
For x = 13,
z = (13 - 10)/2 = 1.5
Looking at the normal distribution table, the probability corresponding to the z score is 0.933
P(x > 13) = 1 - 0.933 = 0.067
Its mean and range . Even if we remove 70 the median is the same. The mean changes also as 580/7 isnt the same as 510/6 and also the range changes as it decreases by 5. Hope it helped :)
Answer:
Move all terms that don't have "y
" in it to the right side and solve.
y
=−
17
/5
+
4
x
/5
Step-by-step explanation:
