Answer: False
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Explanation:
I'll use x in place of p.
The original equation 10x^2-5x = -8 becomes 10x^2-5x+8 = 0 after moving everything to one side.
Compare this to ax^2+bx+c = 0
We have
Plug those three values into the discriminant formula below
d = b^2 - 4ac
d = (-5)^2 - 4(10)(8)
d = 25 - 40*8
d = 25 - 320
d = -295
The discriminant is negative, which means we have no real solutions. If your teacher has covered complex or imaginary numbers, then you would say that the quadratic has 2 complex roots. If your teacher hasn't covered this topic yet, then you'd simply say "no real solutions".
Either way, this quadratic doesn't have exactly one solution. That only occurs when d = 0. Therefore, the original statement is false.
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Answer:
Use demos or a graphing calc.
Step-by-step explanation:
Ok so...
You want to move the decimal point to the right until the number is greater than 1 but less than 10.
The number will end up being 5.2
You moved the decimal point 3 times to the right.
So it will be 5.2 x 10^-3. It is negative because you moved it to the right. The exponent would be positive if you moved it to the left
Maybe solve by dividing. I think 5/6. Sorry math isn’t my strong suit. I’m good at reading.
