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Effectus [21]
3 years ago
8

Hurry i need asap thx

Mathematics
2 answers:
Marta_Voda [28]3 years ago
7 0

Answer: -8

Step-by-step explanation:

soldier1979 [14.2K]3 years ago
3 0

Answer the Answer is -8                                                  

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11 identical pairs of Air Jordan cost $660.What is the cost of one pair?
Crank

Answer:

$60

Step-by-step explanation:

11 identical pairs of Air Jordan cost $660.

To find the cost of one pair, you have simply to divide the total amount paid by the total number of pairs.

Total amount paid = $660

Total number of pairs = 11

The cost of one pair =\$660 : 11=\$60

6 0
4 years ago
Mark buys a treadmill priced at $360.26.Shipping and handling are an additional 10%of the price.How much shipping and handling w
Vinil7 [7]
10% of 360.26 is 36.026 but that answer wouldn’t be it since cents are only in the tenths and hundredths places after the decimal, so you’d probably have to round it up to 36.03
3 0
2 years ago
Set up a rational equation and then solve the following problems. A positive integer is twice another. The difference of the rec
kupik [55]

Answer:

9 and 18

Step-by-step explanation:

2x and x are the numbers

1/x-1/2x=1/18

2/2x-1/2x=1/18

1/2x=1/18

2x=18X=9,

2x=18

The two integers are 9 and 18

3 0
3 years ago
Find the values of the sine, cosine, and tangent for ZA.<br><br> (TOP OF TRIANGLE IS (A))
Sloan [31]

\bigstar\:{\underline{\sf{In\:right\:angled\:triangle\:ABC\::}}}\\\\

  • AC = 7 m
  • BC = 4 m

⠀⠀⠀

\bf{\dag}\:{\underline{\frak{By\:using\:Pythagoras\: Theorem,}}}\\\\

\star\:{\underline{\boxed{\frak{\purple{(Hypotenus)^2 = (Perpendicular)^2 + (Base)^2}}}}}\\\\\\ :\implies\sf (AB)^2 = (AC)^2 + (BC)^2\\\\\\ :\implies\sf (AB)^2 = (AB)^2 = (7)^2 = (4)^2\\\\\\ :\implies\sf (AB)^2 = 49 + 16\\\\\\ :\implies\sf (AB)^2 = 65\\\\\\ :\implies{\underline{\boxed{\pmb{\frak{AB = \sqrt{65}}}}}}\:\bigstar\\\\

⠀⠀⠀⠀━━━━━━━━━━━━━━━━━━━━━

☆ Now Let's find value of sin A, cos A and tan A,

⠀⠀⠀

  • sin A = Perpendicular/Hypotenus = \sf \dfrac{4}{\sqrt{65}} \times \dfrac{\sqrt{65}}{\sqrt{65}} = \pink{\dfrac{4 \sqrt{65}}{65}}

⠀⠀⠀

  • cos A = Base/Hypotenus = \sf \dfrac{7}{\sqrt{65}} \times \dfrac{\sqrt{65}}{\sqrt{65}} = \pink{\dfrac{7 \sqrt{65}}{65}}

⠀⠀⠀

  • tan A = Perpendicular/Base = {\sf{\pink{\dfrac{4}{7}}}}

⠀⠀⠀

\therefore\:{\underline{\sf{Hence,\: {\pmb{Option\:A)}}\:{\sf{is\:correct}}.}}}

4 0
3 years ago
Which expression can be used to change 75 kilometers per hour to meters per minute?
atroni [7]
1h=60min\\1km=1000m\\\\\\75\ km/h=75\cdot\frac{1000}{60}\ m/min=1250\ m/min
4 0
3 years ago
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