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shtirl [24]
3 years ago
13

In a CPM network, the critical path has six activities: A, D, G, H, M, and O. (Use Excel) Determine the following probabilities:

a) The probability that the project will finish by the end of day 64. b) The probability that the project will finish before day 60. c) The probability that the project will finish on day 62. d) The probability that the project will finish after day 70
Mathematics
1 answer:
inysia [295]3 years ago
3 0

Answer:

Hi how are you doing today Jasmine

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Find the Perimeter of Polygon JKLMN. Round to the tenth.
kramer

9514 1404 393

Answer:

  24.1 units

Step-by-step explanation:

This is done using the Pythagorean theorem (or distance formula) to find the lengths of the sides.

For each side of the figure (except the bottom horizontal), you need to identify the dimensions of the right triangle whose hypotenuse is the side of interest. For example, LM is the hypotenuse of a triangle 4 units high and 1 unit wide. The Pythagorean theorem tells you LM has a length of ...

  LM = √(4^2 +1^2) = √17 ≈ 4.12

Similarly ...

  KL = √(2^2 +2^2) = √8 ≈ 2.83

  JK = √(1^2 +6^2) = √37 ≈ 6.08

  NJ = √(5^2 +1^2) = √26 ≈ 5.10

Of course, the length of MN is found by finding the difference of the x-coordinates:

  MN = 3 -(-3) = 6

Then the perimeter is the sum of side lengths:

  4.12 +2.83 +6.08 +5.10 +6.00 = 23.17 ≈ 24.1 . . . units

8 0
3 years ago
This is my question!!!??? I hope you can help me!!
Akimi4 [234]
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3 years ago
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Find the value of tan30+cot30+sin60​
Aliun [14]

Hello!

This is a problem about relating values of the Unit Circle.

First, we need to figure out the specific "points" of each angle measure of 30 and 60.

For the angle measure 30, the point will be (\frac{\sqrt{3}}{2},\frac{1}{2}).

For the angle measure 60, the point will be (\frac{1}{2},\frac{\sqrt{3}}{2}).

The tangent value of a point will be its y value over its x value.

\frac{\frac{1}{2}}{\frac{\sqrt{3}}{2}}=\frac{1}{2}*\frac{2}{\sqrt{3}}=\frac{1}{\sqrt{3}}=\frac{\sqrt{3}}{3}

The cotangent value of a point will be the reciprocal of the tangent value, which we found previously.

\frac{3}{\sqrt{3}}=\frac{3\sqrt{3}}{3}=\sqrt{3}

The sine value of a point will be the y value of the point.

\frac{\sqrt{3}}{2}

So the values we have so far are \frac{\sqrt{3}}{3}+\sqrt{3}+\frac{\sqrt{3}}{2}

Now we have to find the LCD to add these together, which in this case would be 6.

\frac{2\sqrt{3}}{6}+\frac{6\sqrt{3}}{6}+\frac{3\sqrt{3}}{6}

Which adds up to \frac{11\sqrt{3}}{6}, which is in simplest radical form.

Hope this helps!

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3 years ago
And activating the<br> body to respond to information received.<br> I
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Answer:

What?

Step-by-step explanation:

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