3 years ago

Find the zeros on the function f(x)=(x-3)(2x-8)

1 answer:

lawyer [7]3 years ago

6 0

Set both expressions equal to 0

x-3=0
x=3

2x-8=0
2x=8
x=4

your zeroes are 3 and 4

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Anarel [89]

In this case, we must use trigonometry to find the value of x:

$tan(\alpha )=\frac{side-opposite-angle}{side-beside-angle} \\tan(70) = \frac{x}{3} \\3*tan(70) = x\\x = 3*tan(70)\\x = 8.24$

Thus the value of x rounded to the nearest tenth is 8.2

Hope that helps!

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3 years ago

aleksley [76]

Find what is in the middle of them from where the lines meet

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3 years ago

Luda [366]

Answer:

-4

Step-by-step explanation:

27/16 ,-9/4,3..

We need to find the common ration

r = term2 / term 1

= -9/ 4 ÷27/16

copy dot flip

= -9/4 * 16/27 = -4/3

Multiply the last term by the common ratio

3 * -4/3 = -4

The next term is -4

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3 years ago

agasfer [191]

Multiply 3 by 2 and you get six I think

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3 years ago

tester [92]

0.073224 is the answer

8 0

3 years ago