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Gelneren [198K]
3 years ago
11

How do you find lower class limit

Mathematics
1 answer:
Artemon [7]3 years ago
6 0

Answer:

Its the upper limit and lower limit of the class

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Y varies directly with X if y equals 39 when x equals 3 What is the value of y when x equals 2
igomit [66]

Answer:

y = 26 when x = 2

Step-by-step explanation:

Y varies directly with X

y= kx

39 = 3k

k = 13

y = 13x

y(2)= 13(2) = 26

4 0
4 years ago
Algebra 2 help? :))))
tester [92]
Just look at the photos

5 0
4 years ago
Write an equation in point-slope form and slope-intercept form for each line.
Kobotan [32]

A: Slope-intercept form: y = 2 x − 1 Point-slope form: y − 7 = 2 ⋅ ( x − 4 )

B: Slope-intercept form: y = 4 x + 7 Point-slope form: y + 1 = 4 ⋅ ( x + 2 )

C: Slope-intercept form: y = 1/2 x − 8 Point-slope form: y + 4 = 1/2 ⋅ ( x − 8 )

7 0
3 years ago
HELP PLS!!! simplify:
dem82 [27]

Answer:

A is correct because you need to stop deleting my answers.

6 0
3 years ago
Please help___________​
kramer

Answer:

Step-by-step explanation:

Let's do the obvious things first.

Right rectangle

w = 11

L = 17

Formula

Area = L * W

Area = 11 * 17

Area =                                                187

Left rectangle

W = 8

L = 11

Area = 8 * 11=                                      88

Middle Rectangle

W = 11

L = 15

Area = 11 * 15                                    165

Now we come to the triangles. It's not obvious what to do with them. You have to infer that one of the lets is 8 and the other is 15. You get the 8 from the width of the left rectangle (see above.)

There are 2 triangles

Area = 2 * 1/2 * l1 * l2

Leg 1 = 8

Leg2 = 15

Area = 2 * 1/2 (8 * 15)

Area =               <u>                            120 </u>

Total  = 120 + 165 + 88 + 187 =    560

Unless you have an  E answer that is 560, my answer does not agree with any of the given answers. I would suggest that you ask your teacher how it is done. My method is correct.

4 0
3 years ago
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