Question

Someone please help me with this ! (No links) I would really appreciate the help !

Answer 1

Answer: Since this is the right triangle so

$Sin B = \frac{AC}{AB} =\frac{AC}{6} \\=> AC = sin(20) * 6 = 5.478 = 5.48$

Apply Pythagorean theorem:

$AC^{2} +CB^{2} =AB^{2} \\5.48^{2} +CB^{2} =6^{2}$

$CB = \sqrt{6^{2} -5.48^{2} } = 2.44$