Answer:
Step-by-step explanation:
I do t k iw
Equals 1 over 7 because 63/9 is 7. The answer is 1/7
Answer:
I think it's 500
Step-by-step explanation:
Since each decagon is 10 Units of perimeter each 50 Decagons (50*10) is 500
Answer:
C (11.3) = 165
P (3,3) = 6
Step-by-step explanation:
We want to select 3 players out of 11 regardless of the order. That is, there is no difference between selecting the players {2,5,7} or {7,2,5}
Then we use the formula of combinations:
![C(n, r) = \frac{n!}{r!(n-r)!}\\\\C(11, 3) = \frac{n!}{r!(n-r)!}\\\\C(11, 3) = 165](https://tex.z-dn.net/?f=C%28n%2C%20r%29%20%3D%20%5Cfrac%7Bn%21%7D%7Br%21%28n-r%29%21%7D%5C%5C%5C%5CC%2811%2C%203%29%20%3D%20%5Cfrac%7Bn%21%7D%7Br%21%28n-r%29%21%7D%5C%5C%5C%5CC%2811%2C%203%29%20%3D%20165)
There are 165 ways to choose 3 players out of 11.
Now we want to know how many ways you can designate those 3 players as first, second and third. Now if we care about the order of selection. Then we use permutations.
![P(n, r) = \frac{n!}{(n-r)!}\\\\P(3,3) = \frac{3!}{(3-3)!}\\\\P(3,3) = 6](https://tex.z-dn.net/?f=P%28n%2C%20r%29%20%3D%20%5Cfrac%7Bn%21%7D%7B%28n-r%29%21%7D%5C%5C%5C%5CP%283%2C3%29%20%3D%20%5Cfrac%7B3%21%7D%7B%283-3%29%21%7D%5C%5C%5C%5CP%283%2C3%29%20%3D%206)
They can be designated in 6 different ways
Cost of 1 pack of trading cards = xTotal packs purchased = 10Cost of 10 packs before discount (A) = 10 * xDiscount percentage = 20 %Discount amount per pack = (20/100) * xDiscount amount for 10 packs (B) = (20/100) * x * 10Cost of 10 packs after discount is (A) - (B) = (10 * x) - ((20/100) * x * 10)Simplifying, we get x * (10 - 200/100) = x * (10 - 2) = x * 8 = 8 * xCost of shipping = $3.99Total cost of 10 packs of trading cards after discount and including cost of shipping can be represented by the algebraic expression 8 * x + 3.99 or 8x + 3.99