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IrinaK [193]
2 years ago
7

Select all expressions that at equivalent to the expression 3x + 5. A. 9x − (−5 + 6x) B. 9x − (5 − 6x) C. 9x − (6x + 5) D. 9x −

(6x − 5) E. 9x − (−6x + 5)
Mathematics
1 answer:
tankabanditka [31]2 years ago
7 0

Answer:

A. 9x − (−5 + 6x)

D. 9x − (6x − 5)

Step-by-step explanation:

Select all expressions that at equivalent to the expression 3x + 5.

To get our answer, we have to solve each option

A. 9x − (−5 + 6x)

= 9x + 5 - 6x

= 9x - 6x + 5

= 3x + 5

Option A is correct

B. 9x − (5 − 6x)

= 9x - 5 + 6x

= 9x + 6x - 5

= 15x - 5

Option B is wrong

C. 9x − (6x + 5)

9x - 6x - 5

= 3x - 5

Option C is wrong

D. 9x − (6x − 5)

= 9x - 6x + 5

= 3x + 5

Option D is correct

E. 9x − (−6x + 5)

= 9x + 6x - 5

= 15x - 5

Therefore, Option A and D are the correct options with the right expressions

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The areas of two similar triangles are 72dm2 and 50dm2. The sum of their perimeters is 226dm. What is the perimeter of each of t
astraxan [27]

Answer:

Hence, the perimeter of the triangles are:

P=123.2727 dm

P'=102.7272 dm

Step-by-step explanation:

In two similar triangles:

The ratio of the areas of two triangle is equal to the square of their perimeters.

Let A and A' represents the area of two triangles and P and P' represents their perimeter.

Then they are related as:

\dfrac{A}{A'}=\dfrac{P^2}{P'^2}

We are given:

A=72 dm^2  , A'=50 dm^2

and P+P'=226 dm.-----------(1)

i.e. \dfrac{72}{50}=\dfrac{P^2}{P'^2}\\\\\dfrac{36}{25}=\dfrac{P^2}{P'^2}

on taking square root on both the side we get:

\dfrac{P}{P'}=\dfrac{6}{5}\\\\P=\dfrac{6}{5}P'

Now putting the value of P in equation (1) we obtain:

\dfrac{6}{5}P'+P'=226\\\\\dfrac{6P'+5\times P'}{5}=226\\\\\dfrac{6P'+5P'}{5}=226\\\\11P'=226\times 5\\\\11P'=1130\\\\P'=\dfrac{1130}{11}=102.7272

Hence,

P=226-102.7272=123.2727

Hence, the perimeter of the triangles are:

P=123.2727 dm

P'=102.7272 dm

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