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IrinaK [193]
2 years ago
7

Select all expressions that at equivalent to the expression 3x + 5. A. 9x − (−5 + 6x) B. 9x − (5 − 6x) C. 9x − (6x + 5) D. 9x −

(6x − 5) E. 9x − (−6x + 5)
Mathematics
1 answer:
tankabanditka [31]2 years ago
7 0

Answer:

A. 9x − (−5 + 6x)

D. 9x − (6x − 5)

Step-by-step explanation:

Select all expressions that at equivalent to the expression 3x + 5.

To get our answer, we have to solve each option

A. 9x − (−5 + 6x)

= 9x + 5 - 6x

= 9x - 6x + 5

= 3x + 5

Option A is correct

B. 9x − (5 − 6x)

= 9x - 5 + 6x

= 9x + 6x - 5

= 15x - 5

Option B is wrong

C. 9x − (6x + 5)

9x - 6x - 5

= 3x - 5

Option C is wrong

D. 9x − (6x − 5)

= 9x - 6x + 5

= 3x + 5

Option D is correct

E. 9x − (−6x + 5)

= 9x + 6x - 5

= 15x - 5

Therefore, Option A and D are the correct options with the right expressions

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kipiarov [429]

Answer:

BN=4\ \text{in}

AN=2\ \text{in}

AC=\sqrt{5}\ \text{in}

Step-by-step explanation:

Let BN=x

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AB=a=2\sqrt{5}\ \text{in}

AC=b

We have the relation

\dfrac{BC}{AB}=\dfrac{AB}{BN}\\\Rightarrow \dfrac{c}{a}=\dfrac{a}{x}\\\Rightarrow c=\dfrac{a^2}{x}\\\Rightarrow x+1=\dfrac{a^2}{x}\\\Rightarrow x^2+x=20\\\Rightarrow x^2+x-20=0\\\Rightarrow x=\frac{-1\pm \sqrt{1^2-4\times 1\times \left(-20\right)}}{2\times 1}\\\Rightarrow x=4,-5

\boldsymbol{BN=4\ \text{in}}

h=\sqrt{a^2-x^2}\\\Rightarrow h=\sqrt{(2\sqrt{5})^2-4^2}\\\Rightarrow h=2\ \text{in}

\boldsymbol{AN=2\ \text{in}}

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\boldsymbol{AC=\sqrt{5}\ \text{in}}

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2 years ago
Please help me its about solving system by substitution
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Answer:

(-3, 4)

General Formulas and Concepts:

<u>Pre-Algebra</u>

Order of Operations: BPEMDAS

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  2. Parenthesis
  3. Exponents
  4. Multiplication
  5. Division
  6. Addition
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  • Left to Right

Equality Properties

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  • Addition Property of Equality
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<u>Algebra I</u>

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Step-by-step explanation:

<u>Step 1: Define Systems</u>

y = -x + 1

2x + 3y = 6

<u>Step 2: Solve for </u><em><u>x</u></em>

<em>Substitution</em>

  1. Substitute in <em>y</em>:                    2x + 3(-x + 1) = 6
  2. Distribute 3:                         2x - 3x + 3 = 6
  3. Combine like terms:           -x + 3 = 6
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<u>Step 3: Solve for </u><em><u>y</u></em>

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  2. Substitute in <em>x</em>:                        y = -(-3) + 1
  3. Simplify:                                   y = 3 + 1
  4. Add:                                         y = 4
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