If the graph f(x)= 9x^2+37x+41/3x+5 has an oblique asymptote at y=3x+k what is the value of k
2 answers:
Answer:
Step-by-step explanation:
The oblique asymptote of
,
We perform the long division as shown in the attachment.
The quotient is;
Comparing to 3x+k
Hence the value of k is
Answer:
Step-by-step explanation:
To find out oblique asymptote we divide the polynomials using long division
To find quotient divide the first term. then multiply the answer with 3x+5 and write it down. Subtract it from the top. Repeat the process till we get remainder.
------------------------------
-------------------------------------(Subtract)
------------------------------------(subtract)
Quotient is that is our oblique asympotote
the value of k is 22/3
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domain represents the x values so for example in a diagonal line that continues infinitely, the domain is all real numbers or (-infinity, infinity)
range represents y values so it would also be all real numbers or (-infinity, infinity)
let’s say there is a line (refer to pic) that moves ONLY from point (-3, -1) and (2, 2)
the domain would be [-3, 2]
we use brackets because it’s a real number unlike infinity (also because it’s a closed circle on the graph; if the graph had an open circle you would use a parenthesis)
and the range would be [-1, 2]
if you have any more questions about this explanation feel free to ask!
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