Put the numbers in order...
4,5,6,6,7,8,9,9,10,10,12,12,14,15
Q1 = (6 + 6) / 2 = 12/2 = 6
Q2 (median) = (9 + 9)/2 = 18/2 = 9
Q3 = (12 + 12) / 2 = 24/2 = 12
Q3 - Q1 = 12 - 6 = 6 (this is actually the interquartile range (IQR)
Answer:
The 99% confidence interval would be given by (0.054;0.154)
. So we are confident at 99% that the true proportion of people that they did work at home at least once per week is between 0.054 and 0.154
Step-by-step explanation:
For this case we can estimate the population proportion of people that they did work at home at least once per week with this formula:

We need to find the critical value using the normal standard distribution the z distribution. Since our condifence interval is at 99%, our significance level would be given by
and
. And the critical value would be given by:
The confidence interval for the mean is given by the following formula:
If we replace the values obtained we got:
The 99% confidence interval would be given by (0.054;0.154)
. So we are confident at 99% that the true proportion of people that they did work at home at least once per week is between 0.054 and 0.154
Answer:
e) cos(90° - x)
Step-by-step explanation:
we know that
If two angles are complementary, the cofunction identities state that the sine of one equals the cosine of the other and vice versa
The complementary angle of angle x is equal to (90-x) degrees
therefore

N=25 You just divide 300 and 12 to get 25!
Answer:
1. 4 is the constant
2. x > -2
3. 2.86 inches
^The formula for the circumference of a circle is C=2∏r, in which r=radius. To find the radius, then, we insert 18 in for the circumference. So 18=2∏r. Solving for r gives 9/∏, or approximately 2.86 inches.
hope this helped:)
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