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3 years ago

15

What is the volume of a rectangular prism with the dimensions

1 answer:

snow_tiger [21]3 years ago

6 0

Para calcular el volumen de un prisma rectangular, multiplica sus 3 dimensiones: <u>longitud x ancho x altura.</u> <u> </u>

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What’s the midpoint of the line segment joining A and B<br><br> A(2,-5);B(6,1)

IRISSAK [1]

$\bf ~~~~~~~~~~~~\textit{middle point of 2 points } \\\\ A(\stackrel{x_1}{2}~,~\stackrel{y_1}{-5})\qquad B(\stackrel{x_2}{6}~,~\stackrel{y_2}{1}) \qquad \left(\cfrac{ x_2 + x_1}{2}~~~ ,~~~ \cfrac{ y_2 + y_1}{2} \right) \\\\\\ \left( \cfrac{6+2}{2}~~,~~\cfrac{1-5}{2} \right)\implies \left( \cfrac{8}{4}~,~\cfrac{-4}{2} \right)\implies (4,-2)$

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3 years ago

4 x (5+5)<br> I need the distributive property and the answer please I need it ASAP!

Paraphin [41]

4 x 5 x 5 is 100 if u distribute

Now 5 + 5 x 4 is 25

5 0

3 years ago

Can someone help me with the question in the image. if correct i will mark as brainliest

Andrews [41]

Answer: i think its B

Step-by-step explanation:

5 0

3 years ago

Simplify the expression

erastova [34]

Answer : A

We need to simplify the given expression

Lets factor numerator first

$2x^2-5x-3$ =(2x+1)(x-3)

$x^2+8x+15$ =(x+5)(x+3)

Now we factor the denominator

$x^2+x-20$ =(x+5)(x-4)

$2x^2+9x+4$ =(2x+1)(x-4)

Now we simplify it

$\frac{(2x+1)(x-3)}{(x+5)(x-4)} * \frac{(x+5)(x+3)}{(2x+1)(x-4)}$

Now cancel out same factors. so we left with

$\frac{(x+3)(x-3)}{(x+4)(x-4)} }$

Now multiply the factors

$\frac{x^2-9}{x^2-16} }$

6 0

3 years ago

Which of the following correctly expresses sin (70) + sin(30) as a product?

JulsSmile [24]

Answer:

2sin50 cos20

Step-by-step explanation:

We need to write sin (70) + sin(30) as a product. The formula used here is :

$\sin A+\sin B=2\sin (\dfrac{A+B}{2})\cos(\dfrac{a-b}{2})$

Here, A = 70 and B = 30

So,

$\sin 70+\sin 30=2\sin (\dfrac{70+30}{2})\cos(\dfrac{70-30}{2})\\\\\sin 70+\sin 30=2\sin 50\cos20$

So, the value of sin (70) + sin(30) is 2sin50 cos20. Hence, the correct option is (c).

7 0

3 years ago