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tatyana61 [14]
2 years ago
6

A cab company charges a $5 pick up fee and $1 for each mile up to 10 miles and $2 per mile for each mile over $10. Which graph c

orrectly represents the charge, y, in dollars for a cab ride of x miles?
(there’s one more graph that i couldn’t fit in the screenshot. if any of these choices are wrong,let me know. it must be the graph that i couldn’t show)

Mathematics
1 answer:
makvit [3.9K]2 years ago
3 0

Answer:

C or the third one

Step-by-step explanation:

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mars1129 [50]

So remember that the distance formula is \sqrt{(x_2-x_1)^2+(y_2-y_1)^2} .

1.

\sqrt{(4-4)^2+(-2-(-5))^2}\\ \sqrt{0^2+3^2}\\ \sqrt{0+9}\\ \sqrt{9}\\ 3

Distance between (4,-5) and (4,-2) is 3 units.

2.

\sqrt{(1-(-1))^2+(1-4)^2}\\ \sqrt{2^2+(-3)^2}\\ \sqrt{4+9}\\ \sqrt{13}

Distance between (1,1) and (-1,4) is √13 (or 3.61 rounded to the hundreths) units.

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3 years ago
Each exterior angle of a regular polygon measures 60 degree how many sides does a polygon have ?
algol13
360/60=6
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4 years ago
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What is the area of a circle with a diameter of 9.2 centimeters? Round your answer ro the nearest hundredth.
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The answer the the problem is A.
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Modeling Exponential Growth and Decay In Exercises 119 and 120, Find the exponential function
Lubov Fominskaja [6]

Answer:

There is no exponential function passing through (1,1) and (5,5).

Step-by-step explanation:

We have the following exponential function

y = Ce^{kt}

The function passes through these two points:

(1,1): This means that when t = 1, y = 1

(5,5): This means that when t = 5, y = 5.

So

(1,1)

y = Ce^{kt}

Ce^{k} = 1

e^{k} = \frac{1}{C}

(5,5)

y = Ce^{kt}

5Ce^{k} = 1

Ce^{k} = \frac{1}{5}

From above, we have that:

e^{k} = \frac{1}{C}

C\frac{1}{C} = \frac{1}{5}

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This means that there is no exponential function passing through (1,1) and (5,5).

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Answer:

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Step-by-step explanation:

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