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forsale [732]
4 years ago
13

Solve for w. 4 = 0.25(w-4.3)

Mathematics
1 answer:
Snezhnost [94]4 years ago
8 0

W=20.3

solve what's in the parenthesis, move the terms, calculate, then divide both sides.

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Find the value of x<br>​
Monica [59]

X= 130°

Step-by-step explanation:

From E, draw EF || AB || CD.

Now, EF || CD and CE is the transversal.

So; <DCE + <CEF = 180° [co. int. <s]

x° + <CEF = 180°

<CEF = (180° – x°).

Again, EF || AB and AE is the transversal.

So; <BAE + <AEF = 180° 01 [co. int. <s ]

105° + <AEC+ <CEF = 180°

105° +25° + (180° – x°) = 180°

x° = 130°

I hope I helped you^_^

7 0
3 years ago
What is the angle of rotation of the minute hand of a clock moving from 6:10 to 7:00?
german
Thank you for posting your question here at brainly. Feel free to ask more questions.  

The best and most correct answer among the choices provided by the question is <span>D.300°</span>.<span>       
    </span><span>
Hope my answer would be a great help for you.</span>
7 0
3 years ago
100-99+98-97+96-95+...+8-7+6-5+4-3+2-1
lina2011 [118]
100-99+98-97+96-95+...+8-7+6-5+4-3+2-1\\\\=(100-99)+(98-97)+(96-95)+...+(4-3)+(2-1)\\\\=\underbrace{1+1+1+...+1}_{50}=\fbox{50}

8 0
3 years ago
Read 2 more answers
Factor f(x) = 15x^3 - 15x^2 - 90x completely and determine the exact value(s) of the zero(s) and enter them as a comma separated
Illusion [34]

Answer:

x=-2,0,3

Step-by-step explanation:

We have been given a function f(x)=15x^3-15x^2-90x. We are asked to find the zeros of our given function.

To find the zeros of our given function, we will equate our given function by 0 as shown below:

15x^3-15x^2-90x=0

Now, we will factor our equation. We can see that all terms of our equation a common factor that is 15x.

Upon factoring out 15x, we will get:

15x(x^2-x-6)=0

Now, we will split the middle term of our equation into parts, whose sum is -1 and whose product is -6. We know such two numbers are -3\text{ and }2.

15x(x^2-3x+2x-6)=0

15x((x^2-3x)+(2x-6))=0

15x(x(x-3)+2(x-3))=0

15x(x-3)(x+2)=0

Now, we will use zero product property to find the zeros of our given function.

15x=0\text{ (or) }(x-3)=0\text{ (or) }(x+2)=0

15x=0\text{ (or) }x-3=0\text{ (or) }x+2=0

\frac{15x}{15}=\frac{0}{15}\text{ (or) }x-3=0\text{ (or) }x+2=0

x=0\text{ (or) }x=3\text{ (or) }x=-2

Therefore, the zeros of our given function are x=-2,0,3.

7 0
4 years ago
Why can't you use the product of powers rule to simplify<br> this expression? Explain.<br> 3^4.2^8
Tema [17]

Answer:

Because the base of this expression is not same.

3 0
3 years ago
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