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Vinvika [58]
3 years ago
11

Plz help me with this will give 25 points, please

Mathematics
2 answers:
goblinko [34]3 years ago
7 0

Answer:

all girls are the same bro

Step-by-step explanation:

mamaluj [8]3 years ago
6 0

Answer:

20

Step-by-step explanation:

An easy way is to just count the grids blocks, which are squares.

There are 18 of these.

For the rest, since they are in the shape of a triangle, they will count as a half grid block.

There are 4 of these, which are 4 halfs, which equal to 2 square blocks.

Add them, 18+2=20

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A. 650

Step-by-step explanation:

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3 years ago
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Evaluate<br> 5-(2w-8)=6w-9
Brilliant_brown [7]

Step-by-step explanation:

Steps

5−(2w−​8)=6w−9

Show Steps

Expand 5−(2w−8):    −2w+13

−2w+13=6w−9

Subtract 13 from both sides

−2w+13−13=6w−9−13

Simplify

−2w=6w−22

Subtract 6w from both sides

−2w−6w=6w−22−6w

Simplify

−8w=−22

Divide both sides by −8

−8w

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−8

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11

4

click her

5 0
3 years ago
Waiting on the platform, a commuter hears an announcement that the train is running five minutes late. He assumes the arrival ti
natima [27]

Answer:

D. 91%

Step-by-step explanation:

Conditional Probability

We use the conditional probability formula to solve this question. It is

P(B|A) = \frac{P(A \cap B)}{P(A)}

In which

P(B|A) is the probability of event B happening, given that A happened.

P(A \cap B) is the probability of both A and B happening.

P(A) is the probability of A happening.

In this question:

Event A: Less than 15 minutes.

Event B: Less than 10 minutes.

We are given the following probability distribution:

f(T = t) = \frac{3}{5}(\frac{5}{t})^4, t \geq 5

Simplifying:

f(T = t) = \frac{3*5^4}{5t^4} = \frac{375}{t^4}

Probability of arriving in less than 15 minutes:

Integral of the distribution from 5 to 15. So

P(A) = \int_{5}^{15} = \frac{375}{t^4}

Integral of \frac{1}{t^4} = t^{-4} is \frac{t^{-3}}{-3} = -\frac{1}{3t^3}

Then

\int \frac{375}{t^4} dt = -\frac{125}{t^3}

Applying the limits, by the Fundamental Theorem of Calculus:

At t = 15, f(15) = -\frac{125}{15^3} = -\frac{1}{27}

At t = 5, f(5) = -\frac{125}{5^3} = -1

Then

P(A) = -\frac{1}{27} + 1 = -\frac{1}{27} + \frac{27}{27} = \frac{26}{27}

Probability of arriving in less than 15 minutes and less than 10 minutes.

The intersection of these events is less than 10 minutes, so:

P(B) = \int_{5}^{10} = \frac{375}{t^4}

We already have the integral, so just apply the limits:

At t = 10, f(10) = -\frac{125}{10^3} = -\frac{1}{8}

At t = 5, f(5) = -\frac{125}{5^3} = -1

Then

P(A \cap B) = -\frac{1}{8} + 1 = -\frac{1}{8} + \frac{8}{8} = \frac{7}{8}

If given the train arrived in less than 15 minutes, what is the probability it arrived in less than 10 minutes?

P(B|A) = \frac{P(A \cap B)}{P(A)} = \frac{\frac{7}{8}}{\frac{26}{27}} = 0.9087

Thus 90.87%, approximately 91%, and the correct answer is given by option D.

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FUTURE SMART QUESTION +25 POINTS PKEASE ANSWER
Rufina [12.5K]

Answer:

18750

Step-by-step explanation:

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3 years ago
Write the equation of the trigonometric graph.
Angelina_Jolie [31]

Answer:

started off from maximum, so f(x) = acos(bx)

max(f(x))=a=4

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the period is T = 2π

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b=1

f(x)=4cos(x)

6 0
2 years ago
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