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vodomira [7]
3 years ago
9

How do i write 7 37/40 as a decimal?

Mathematics
2 answers:
gizmo_the_mogwai [7]3 years ago
8 0
To get 37/40 converted to decimal, you simply divide 37 by 40. 37/40 as a decimal is: 0.925000,

tensa zangetsu [6.8K]3 years ago
7 0
Your answer would be
7.925 
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152 square inches

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OverLord2011 [107]

The four consecutive terms are 2,6,10,14.

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Let the four consecutive terms of an arithmetic progression be (a - 3d), (a - d),(a + d), (a + 3d)

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Thus, adding all the four consecutive terms, we have,

\begin{array}{r}{a-3 d+a-d+a+d+a+3 d=32} \\{4 a=32} \\{a=8}\end{array}

Thus, the value of a is 8.

It is also given that the ratio of the product of first and last term to the product of the two middle terms is 7:15. Thud, we have,

\frac{(a-3d)(a+3d)}{(a-d)(a+d)} =\frac{7}{15}

Simplifying the terms, we have,

$\begin{aligned} \frac{a^{2}-9 d^{2}}{a^{2}-d^{2}} &=\frac{7}{15} \\ 15\left(a^{2}-9 d^{2}\right) &=7\left(a^{2}-d^{2}\right) \\ 15 a^{2}-135 d^{2} &=7 a^{2}-7 d^{2} \\ 8 a^{2} &=128 d^{2} \end{aligned}$

Now, substituting a = 8, we have,

$\begin{aligned} 8(64) &=128 d^{2} \\ 512 &=128 d^{2} \\ 4 &=d^{2} \\ 2 &=d \end{aligned}$

Thus, the value of d is 2.

Now, we shall substitute the value of a and d in the terms (a - 3d), (a - d),(a + d), (a + 3d), we get, the four consecutive terms.

Thus, the four consecutive terms are 2,6,10,14.

8 0
3 years ago
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