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Natalka [10]
3 years ago
5

A gas cylinder contains 1.00 mol He, 1.90 mol Ne, and 1.10 mol Ar. If the total pressure in the cylinder is 2250 mmHg, what is t

he partial pressure of each of the components? Assume constant temperature.PHe=
PNe=
PAr=
Mathematics
1 answer:
Tcecarenko [31]3 years ago
5 0

Answer:

P_he = 562.5 mmHg

P_ne = 1068.75 mmHg

P_ar = 618.75 mmHg

Step-by-step explanation:

Formula for partial pressure is;

Partial pressure = mole fraction × total pressure

Mole fraction of Helium(He); x_he= 1/(1 + 1.9 + 1.1) = 1/4 = 0.25

Mole fraction of Neon(Ne); x_ne = 1.9/(1 + 1.9 + 1.1) = 1.9/4 = 0.475

Mole fraction of argon; x_ar = 1.1/(1 + 1.9 + 1.1) = 1.1/4 = 0.275

Thus;

Partial pressure of He;

P_he = 0.25 × 2250

P_he = 562.5 mmHg

Partial pressure of Ne;

P_ne = 0.475 × 2250

P_ne = 1068.75 mmHg

Partial pressure of Ar;

P_ar = 0.275 × 2250

P_ar = 618.75 mmHg

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