1. Using your straightedge, draw a reference line, if one is not provided.
2. Copy the side of the square onto the reference line, starting at a point labeled A'.
3. Construct a perpendicular at point B' to the line through ab2.
4. Place your compass point at B', and copy the side of the square onto the perpendicular b'g. Label the end of the segment copy as point C.
5. With your compass still set at a span representing AB, place the compass point at C and swing an arc to the left.
6. Holding this same span, place the compass point at A' and swing an arc intersecting with the previous arc. Label the point of intersection as D.
7. Connect points A' to D, D to C, and C to B' to form a square.
Answer:
<h2>10</h2>
Step-by-step explanation:
<em>The answer is 10 because 7 + 3 equals 10!</em>
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<em>This can be proven by adding 7 + 3 or by subtracting in a certain way.</em>
<em>7 + 3 = ?</em>
<em>7 + 1 = 8</em>
<em>7 + 2 = 9</em>
<em>7 + 3 = 10</em>
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<em>You can show more work by subtracting your answer or 10 in this case, which means that you subtract 7 by 10 or 3 by 10, either way is ok.</em>
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<em>If you subtract 7 by 10, ( 10 - 7 ) then you get 3</em>
<em>If you subtract 3 by 10, ( 10 - 3 ) then you get 7</em>
<em>If the number you subtracted matches the number that you didn't subtract, then your answer is correct.</em>
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<em>Hope this helps! <3</em>
<h3>
Answer is ED</h3>
note: ED is the same as DE. The order of the segment letters does not matter.
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Explanation:
In the sequence ABC, the letter B is the second letter and A is the first.
So the corresponding segment to BA will have its first slot be the second letter of DEF, and its second slot be the first letter of DEF. That's how I'm getting ED for the answer. It is the same as DE because it's the same segment.
The corresponding sides are congruent due to the CPCTC which stands for "corresponding parts of congruent triangles are congruent".
9^5 is 9*9*9*9*9 you * 9 by how ever many little number there is so you get 59049
and with 9^3 its 9*9*9 729
its NEVER 9*3 or 9*5 you have to times the same number () time the littler number it telling you how many time to do so