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jarptica [38.1K]
3 years ago
9

dle" class="latex-formula">
find the formula​
Mathematics
1 answer:
mars1129 [50]3 years ago
8 0

Answer:

Step-by-step explanation:

I don't know what you mean by formula but I will simplify the surd for you.

\sqrt{128} = \sqrt{64(2)} = 8\sqrt{2}

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At a graduation dinner, an equal number of guests were seated at each of 12 large tables, and 8
miskamm [114]
Answer::: A. 12n -8 =128
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3 years ago
How would you set up question 4?
Pavel [41]

Step-by-step explanation:

please mark me as brainlest

5 0
2 years ago
Read 2 more answers
How to solve and what is the answer
TiliK225 [7]
Two ways: 
1) guess factors(trial and error)
2) use quadratic formula.
If you use this method then a = -3, b = -6 and c = -1


x = -b +/- [sqrt(b^2 -4ac)/2a]
substituting a, b, and c into our equation we get:
x = - (-6)+/- [sqrt ((-6)^2) - 4(-3)(-1))/2 (-3)]
x = + 6 +/- [sqrt (36 -4 (3)/-6)]  if I didnt make a mistake in my signs
x = + 6 +/- [sqrt (36 -12)/-6)]
x = 6 +/- [sqrt (24)/-6]  but sqrt 6 x sqrt of 4 = sqrt 24 hence
x = 6 +/-  [ sqrt 6 x sqrt 4 /-6] that is:
x = 6 +/- [sqrt 6 x 2 /-6 ]
so x = 6 + [sqrt 6 x 2/-6] and x = 6 - [sqrt 6 x 2/-6]

7 0
3 years ago
Find the probability of at least three successes in six trials of a binomial experiment in which the probability of success is 5
Amanda [17]

Answer:

31.3%

Step-by-step explanation:

Start by doing the binomial expansion of (x+y)^6 where x represents success. This is  

(x^6y^0) + 6(x^5y^1) +15(x^4y^2) +20(x^3y^3) +15(x^2y^4) +6(x^1y^5) +(x^0y^6)  

We are interested in the x^3y^3 term which represents exactly 3 successes. Since the probability of success and failure are both .5 we should be able to figure this out just using the coefficients of the terms which is  

20/64 = .3125 which is 31.25% Rounding yo the nearest tenth gives us

8 0
3 years ago
Pleas help me ASAP thank you :)
RoseWind [281]

Answer:

11

Step-by-step explanation:

it says 11

8 0
3 years ago
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