an = a1r^(n-1)
a5 = a1 r^(5-1)
-6 =a1 r^4
a2 = a1 r^(2-1)
-48 = a1 r
divide
-6 =a1 r^4
---------------- yields 1/8 = r^3 take the cube root or each side
-48 = a1 r 1/2 = r
an = a1r^(n-1)
an = a1 (1/2)^ (n-1)
-48 = a1 (1/2) ^1
divide by 1/2
-96 = a1
an = -96 (1/2)^ (n-1)
the sum
Sn = a1[(r^n - 1/(r - 1)]
S18 = -96 [( (1/2) ^17 -1/ (1/2 -1)]
=-96 [ (1/2) ^ 17 -1 /-1/2]
= 192 * [-131071/131072]
approximately -192
Answer:
5,789
Step-by-step explanation:
I got 5,789 because there are 9 one digit numbers. 1-9 -> 9x1=9. There are 90 two digit numbers. (10-99)-> 90x2=180. There are 900 three digit numbers. (100-999)-> 900x3=2700. There are 725 four digit numbers. (1000-1724)-> 724x4= 2900. Then, I added 9+180+2700+2900=5789.
In conclusion, the total number of digits required in numbering a book that has 1724 pages is 5789.
Answer:
6 sides of the hexagon * one side length of 3 inches = 18
Step-by-step explanation:
Answer:
a) K3050 and b) K1150
Step-by-step explanation:
a) Add all his expenditures
i.e: K300+K150+K100
=K3050
b) Subtract the remaining of his spendings from the total
i.e: K4209 - K3050
=K1150
Answer:
3
Step-by-step explanation:
Integers: 0, 1, 2, 3, 4
0 + 1 + 2 + 3 + 4 = 10
