Answer:
A
Step-by-step explanation:
So we have the equation:
First, let's subtract 16 from both sides:
Now, let's divide both sides by 3:
Remember that with fractional exponents, we can move the denominator into the root position. Therefore:
![(\sqrt[3]{x-4})^4=16](https://tex.z-dn.net/?f=%28%5Csqrt%5B3%5D%7Bx-4%7D%29%5E4%3D16)
Let's take the fourth root of both sides. Since we're taking an even root, make sure to have the plus-minus symbol!
![\sqrt[3]{x-4} =\pm 2](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7Bx-4%7D%20%3D%5Cpm%202)
Cube both sides. Since we're cubing, the plus-minus stays.
Add 4 to both sides.
Calculator:
So, our answer is A.
And we're done!
Hello!
Subtract the cost of the gas from Julie's total earnings find what Julie's profit was.
18 - 5.75 = 12.25
A N S W E R:
Julie's profit is $12.25.
The frequency of A7, which is two octaves above A5, is 3520 (880 x 2 x 2) Hz. The octave term is used in the musical composition to relate the same notes in the higher or lower scale of notes. The note in the one octave higher scale have a doubled frequency than in the neutral scale and The note in the one octave lower scale have a half frequency than in the neutral scale.
21 / \
<span> 3 7 lol more or less</span>
Let h represent the height of the trapezoid, the perpendicular distance between AB and DC. Then the area of the trapezoid is
Area = (1/2)(AB + DC)·h
We are given a relationship between AB and DC, so we can write
Area = (1/2)(AB + AB/4)·h = (5/8)AB·h
The given dimensions let us determine the area of ∆BCE to be
Area ∆BCE = (1/2)(5 cm)(12 cm) = 30 cm²
The total area of the trapezoid is also the sum of the areas ...
Area = Area ∆BCE + Area ∆ABE + Area ∆DCE
Since AE = 1/3(AD), the perpendicular distance from E to AB will be h/3. The areas of the two smaller triangles can be computed as
Area ∆ABE = (1/2)(AB)·h/3 = (1/6)AB·h
Area ∆DCE = (1/2)(DC)·(2/3)h = (1/2)(AB/4)·(2/3)h = (1/12)AB·h
Putting all of the above into the equation for the total area of the trapezoid, we have
Area = (5/8)AB·h = 30 cm² + (1/6)AB·h + (1/12)AB·h
(5/8 -1/6 -1/12)AB·h = 30 cm²
AB·h = (30 cm²)/(3/8) = 80 cm²
Then the area of the trapezoid is
Area = (5/8)AB·h = (5/8)·80 cm² = 50 cm²
