F( x ) = ( x - 1 ) ( x + 2i )( x - 2i ), because the zeroes are 1, -2i, +2i ;
f( x ) = ( x - 1 )( x^2 - 4i^2 ) = ( x - 1 )( x^2 + 4 ) = x^3 - x^2 + 4x - 4 ;
No.
Double 5 and add 1 is 5(2)+1 = 11
Add 1 to 5 then double it: (1+5)2 = 12
Answer:
50%
Step-by-step explanation:
The P(even or divisor of 28) = P(even) + P(divisor of 28) - P(even and divisor of 28). The P(even) = 2/4 = 1/2. The P(divisor of 28) = 2/4 = 1/2. The P(even and divisor of 28) = 2/4 = 1/2 as 2,4 are even numbers and divisors of 28.
1/2 + 1/2 - 1/2 = 1/2 = 50%
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