C = 5/9(F - 32)
C = -30
-30 = 5/9(F - 32)
-30 = 5/9F - 160/9
-30 + 160/9 = 5/9F
-270/9 + 160/9 = 5/9F
-110/9 = 5/9F
-110/9 * 9/5 = F
- 990/45 = F
- 22 = F
C = 5/9(F - 32)
C = 130
130 = 5/9F - 160/9
130 + 160/9 = 5/9F
1170/9 + 160/9 = 5/9F
1330/9 = 5/9F
1330/9 * 9/5 = F
11970/45 = F
266 = F
So in Fahrenheit temp, the the car is protected between -22 F and 266 F
Answer:
h = yX -yr
Step-by-step explanation:
X=r-h/y
X - r = h/y
y*(X-r) = h
h = yX -yr
7√7
using the ' rule of radicals '
• √a × √b ⇔ √ab
simplifying the radicals
√28 = √(4 × 7 ) = √4 × √7 = 2√7
√63 = √(9 × 7) =√9 × √7 = 3√7
√112 = √(16 × 7 ) = √16 × √7 = 4√7
substituting into the expression
3(2√7) - 5(3√7) + 4(4√7) = 6√7 - 15√7 + 16√7 = 7√7
Both missing angles are 45°
I did the problem and I got negative 4 over 9
