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kondor19780726 [428]
2 years ago
6

GIVING BRAINLIEST!!!

Mathematics
1 answer:
mezya [45]2 years ago
8 0

Answer:

D, (6,1), (8,8), (12,22), (20,50)

Step-by-step explanation:

Hope this helps!! :D

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If $5000 is invested at a rate of 3% interest
harkovskaia [24]

The value of the investment in 5 years is $5805.9

<h3>What is Interest ?</h3>

Interest is the amount earned over years for the amount invested.

It is given that

Principal = $5000

Rate = 3%

Compounded Quarterly

Time = 5 years

Amount = ?

The Amount is given by the formula

Amount = P( 1 + (r/n))ⁿˣ

Here n = t = time period for which the investment has been done.

Amount = 5000( 1+(3/4 * 100)⁴ˣ⁵

Amount = 5000 (1.16)

Amount = $ 5805.9

Therefore , The value of the investment in 5 years is $5805.9

To know more about Interest

brainly.com/question/13324776

#SPJ1

7 0
1 year ago
Blank precent of 200miles is 150 miles
gavmur [86]
150/200×100%=75%
75% of 200 miles is 150 miles
5 0
3 years ago
Read 2 more answers
What percent of 200 is 290
GrogVix [38]

\frac{290}{200} * 100 = 1.45 * 100 = 145.

So, Our final answer is 145%
8 0
2 years ago
Read 2 more answers
Question 7: Timani bought a video game console and some games for $350. The video game
lutik1710 [3]

None of these are right

y=$350 because that is her total.

m=$25 because each game cost that.

B=$200 because that's how much the console cost.

$350=$25x+$200

3 0
3 years ago
At an airport, 76% of recent flights have arrived on time. A sample of 11 flights is studied. Find the probability that no more
I am Lyosha [343]

Answer:

The probability is  P( X \le 4 ) = 0.0054

Step-by-step explanation:

From the question we are told that

   The percentage that are on time is  p =  0.76

   The  sample size is n =  11

   

Generally the percentage that are not on time is

     q =  1- p

     q =  1-  0.76

     q = 0.24

The  probability that no more than 4 of them were on time is mathematically represented as

        P( X \le 4 ) =  P(1 ) +  P(2) + P(3) +  P(4)

=>     P( X \le 4 ) =  \left n } \atop {}} \right.C_1 p^{1}  q^{n- 1} +   \left n } \atop {}} \right.C_2p^{2}  q^{n- 2} +  \left n } \atop {}} \right.C_3 p^{3}  q^{n- 3}  +  \left n } \atop {}} \right.C_4 p^{4}  q^{n- 4}

P( X \le 4 ) =  \left 11 } \atop {}} \right.C_1 p^{1}  q^{11- 1} +   \left 11 } \atop {}} \right.C_2p^{2}  q^{11- 2} +  \left 11 } \atop {}} \right.C_3 p^{3}  q^{11- 3}  +  \left 11 } \atop {}} \right.C_4 p^{4}  q^{11- 4}

P( X \le 4 ) =  \left 11 } \atop {}} \right.C_1 p^{1}  q^{10} +   \left 11 } \atop {}} \right.C_2p^{2}  q^{9} +  \left 11 } \atop {}} \right.C_3 p^{3}  q^{8}  +  \left 11 } \atop {}} \right.C_4 p^{4}  q^{7}

= \frac{11! }{ 10! 1!}  (0.76)^{1}  (0.24)^{10} +   \frac{11!}{9! 2!}  (0.76)^2 (0.24)^{9} + \frac{11!}{8! 3!}  (0.76)^{3}  (0.24)^{8}  + \frac{11!}{7!4!}  (0.76)^{4}  (0.24)^{7}

P( X \le 4 ) = 0.0054

4 0
3 years ago
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