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3 years ago

HeLp! the question is on the picture.

Mathematics

1 answer:

aleksandrvk [35]3 years ago

4 0

Answer:

tan ∅ = 16/12

Step-by-step explanation:

Once again here are the trigonometric ratios

Sin = Opposite over Hypotenuse

Cos = Adjacent over Hypotenuse

Tan = Opposite over Tangent

We are asked to find tan ∅

Looking at the trigonometric ratios we see that tan = opposite over adjacent

So we find the side length opposite of the indicated angle (∅) which would be 16 then we find the angle adjacent angle ( the side that is not the hypotenuse nor the opposite ) so the adjacent of angle ∅ is 12

so tan ∅ = opposite (16) over adjacent (12)

tan ∅ = 16/12

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HELP HELP HELP I NEED HELPPP can anyone answer this the question is on the picture it would help a lot please!!!

forsale [732]

It’s -1/2 (negative 1 over 2)

4 0

3 years ago

What is the slope of the line given by the equation -3x = 30 - 5y?

zaharov [31]

Answer:

The slope of the line given by the equation -3x=30-5y is $\frac{3}{5}$ .

Step-by-step explanation:

-3x=30-5y

Move the -3x to the right side of the equal sign and the -5y to the left.

5y=30+3x

By switching them to opposite sides, their sign changes from - to +.

Then, divide both sides by 5 in order to isolate the y.

$\frac{5y}{5} = \frac{30+3x}{5}$

You get:

According to y=mx+b, mx refers to the slope.

In this case, the slope would be $\frac{3}{5}$ .

8 0

3 years ago

What is the mixed number form<br> of 33/8

goblinko [34]

HCF of 8 that will go as much as possible to 33

4*8=32 and denominator is 8

33-32=1 which is the numerator

Answer is :

4 1/8

4 0

3 years ago

Read 2 more answers

If you do these ill give brainliest!! someone smart please help. im struggling

IRISSAK [1]

ANSWER:
15
32
31
10
23
6.5
35
4.8
63
66
200
72
Solution:
Say you have a triangle that is 2.5 by 1
The Number that comes first is the base and there’s only one bass and there’s two sides in those size are 1 so 1×2 is 2+2.5=4.5 so all you’re doing is adding up all the sides together on any shape

4 0

3 years ago

A golfball is hit from the ground with an initial velocity of 200 ft/sec. The horizontal distance that the golfball will travel,

algol13

Answer:

The golfball launched with an initial velocity of 200ft/s will travel the maximum possible distance which is 1250 ft when it is hit at an angle of $\pi/4$ .

Step-by-step explanation:

The formula from the maximum distance of a projectile with initial height h=0, is:

$d(\theta)=\frac{v_i^2sin(2\theta)}{g}$

Where $v_i$ is the initial velocity.

In the closed interval method, the first step is to find the values of the function in the critical points in the interval which is $[0, \pi/2]$ . The critical points of the function are those who make $d'(\theta)=0$ :

$d(\theta)=\frac{v_i^2\sin(2\theta)}{g}\\d'(\theta)=\frac{v_i^2\cos(2\theta)}{g}*(2)\\d'(\theta)=\frac{2v_i^2\cos(2\theta)}{g}$

$d'(\theta)=0\\\frac{2v_i^2\cos(2\theta)}{g}=0\\\cos(2\theta)=0\\2\theta=\pi/2,3\pi/2,5\pi/2,...\\\theta=\pi/4,3\pi/4,5\pi/4,...$

The critical value inside the interval is $\pi/4$ .

$d(\theta)=\frac{v_i^2sin(2\theta)}{g}\\d(\pi/4)=\frac{v_i^2sin(2(\pi/4))}{g}\\d(\pi/4)=\frac{v_i^2sin(\pi/2)}{g}\\d(\pi/4)=\frac{v_i^2(1)}{g}\\d(\pi/4)=\frac{(200)^2}{32}\\d(\pi/4)=\frac{40000}{32}\\d(\pi/4)=1250ft$

The second step is to find the values of the function at the endpoints of the interval:

$d(\theta)=\frac{v_i^2sin(2\theta)}{g}\\\theta=0\\d(0)=\frac{v_i^2sin(2(0))}{g}\\d(0)=\frac{v_i^2(0)}{g}=0ft\\\theta=\pi/2\\d(\pi/2)=\frac{v_i^2sin(2(\pi/2))}{g}\\d(\pi/2)=\frac{v_i^2sin(\pi)}{g}\\d(\pi/2)=\frac{v_i^2(0)}{g}=0ft$

The biggest value of f is gived by $\pi/4$ , therefore $\pi/4$ is the absolute maximum.

In the context of the problem, the golfball launched with an initial velocity of 200ft/s will travel the maximum possible distance which is 1250 ft when it is hit at an angle of $\pi/4$ .

4 0

3 years ago