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fredd [130]
3 years ago
7

. y - 6 = 4(x - 4) Which of the following shows a graph of the equation above?

Mathematics
1 answer:
Phantasy [73]3 years ago
7 0

Answer:

z.

Step-by-step explanation:

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ABC has side lengths that are each equal to
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Step-by-step explanation:no

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3a2 + 16a + 5<br> a2 – 7a + 10
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This is thw answer:


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3 years ago
Which graph represents the solution set to this system of equations? y = –1 2 x + 3 and y = 1 2 x - 1 On a coordinate plane, a l
vivado [14]

Answer:

On a coordinate plane, a line goes through (0, 3) and (2, 2) and another line goes through (0, negative 1) and (2, 0).

Step-by-step explanation:

Given that the system of equations are:

y = –1 /2 x + 3 and y = 1 /2 x - 1

Let us first try the first option

On a coordinate plane, a line goes through (- 4, 1) and (0, 3) and another line goes through (-2, - 2) and (0,- 1)

The slope M1 = (3-1)/(0--4) = 2/4 = 1/2

The calculated slope is positive. But the slope of the first equation is negative. So we ignore the first option.

The next option that makes sense is the last option. That is

On a coordinate plane, a line goes through (0, 3) and (2, 2) and another line goes through (0, -1) and (2, 0). So let also try it by calculating the two slopes

M1 = (2-3)/(2-0) = -1/2 ( perfect)

M2 = (0- -1)/(2-0) = 1/2 (perfect)

Because, from the two equations

y = –1 /2 x + 3 and y = 1 /2 x - 1

The slope of the first is negative and the slope of the second is positive. Also, they have a corresponding intercept which are positive 3 and negative 1

4 0
3 years ago
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What kind of triangle is this?<br> 73°<br> 75°<br> acute<br> Submit<br> 32°<br> right<br> obtuse
puteri [66]
Acute!!! because it’s small
3 0
1 year ago
Read 2 more answers
Write the standard form of the quadratic equation modeled by the points shown in the table below. x -1 0 1 2 3 y -20 -6 2 4 0
disa [49]
We know that
The Standard Form of a Quadratic Equation<span> looks like this
</span> ax²<span> + bx + c = 0
</span>
we have 
<span>x -1    0 1 2 3
y -20 -6 2 4 0

for x=0   y=-6
then
</span> y=ax² + bx + c -------->  -6=a*0² + b*0 + c ---------> c=-6

for y=0  x=3
then
 y=ax² + bx + c------->  0=a*3² + b*3 -6---------> 9a+3b=6----> equation 1

for x=2  y=4

then

 y=ax² + bx + c-----> 4=a*2² + b*2 -6-----> 4=4a+2b-6-----> 4a+2b=10----> a=2.5-0.5b----> equation 2

 

I substitute 2 in 1

9*[2.5-0.5b]+3b=6------> 22.5-4.5b+3b=6------> 1.5b=16.5------> b=11

a=2.5-0.5*11------> a=2.5-5.5------> a=-3

The Standard Form of a Quadratic Equation is

 ax² + bx + c = 0--------> -3x²+11x-6=0


the answer is

-3x²+11x-6=0

 See the attached figure 


5 0
3 years ago
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