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fredd [130]
2 years ago
7

. y - 6 = 4(x - 4) Which of the following shows a graph of the equation above?

Mathematics
1 answer:
Phantasy [73]2 years ago
7 0

Answer:

z.

Step-by-step explanation:

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A passenger in a vehicle should not
grin007 [14]

Answer:

C. Distract the driver

Step-by-step explanation:

hope it helps

5 0
3 years ago
(19) Geometry pls help
gogolik [260]
Yes it is possible to prove this is a parallelogram.

XN = NZ means the diagonal XZ has been bisected
The same goes for diagonal WY (because NY = NW)

Furthermore, we have the pair of vertical angles XNY and ZNW which are congruent

Through SAS, we can say that triangles XNY and ZNW are congruent

Using CPCTC, we can get to the fact that angle NWZ = angle NYX which are alternate interior angles leading to proving that XY || WZ

----------------------

If you repeat those steps above, but focus on triangles WNX and YNZ, we can prove that XW || YZ

----------------------

After proving that XY || WZ and XW || YZ, this is enough to prove we have a parallelogram as the opposite sides are parallel.

3 0
3 years ago
I NEED HELP PLEASE, THANKS! :)
KIM [24]

Answer:  tan(14x)

<u>Step-by-step explanation:</u>

Consider the Sum Formula for tan:

tan(A + B)=\dfrac{tan(A)+tan(B)}{1-tan(A)(tan(B)}\\\\\\tan(9x+5x)=\dfrac{tan(9x)+tan(5x)}{1-tan(9x)(tan(5x)}\\\\\\\large\boxed{tan(14x)}=\dfrac{tan(9x)+tan(5x)}{1-tan(9x)(tan(5x)}

3 0
3 years ago
Read 2 more answers
If sin(x) = 5/13, and x is in quadrant 1, then tan(x/2) equals what?
Rufina [12.5K]
x is in quadrant I, so 0, which means 0, so \dfrac x2 belongs to the same quadrant.

Now,

\tan^2\dfrac x2=\dfrac{\sin^2\frac x2}{\cos^2\frac x2}=\dfrac{\frac{1-\cos x}2}{\frac{1+\cos x}2}=\dfrac{1-\cos x}{1+\cos x}

Since \sin x=\dfrac5{13}, it follows that

\cos^2x=1-\sin^2x\implies \cos x=\pm\sqrt{1-\left(\dfrac5{13}\right)^2}=\pm\dfrac{12}{13}

Since x belongs to the first quadrant, you take the positive root (\cos x>0 for x in quadrant I). Then

\tan\dfrac x2=\pm\sqrt{\dfrac{1-\frac{12}{13}}{1+\frac{12}{13}}}

\tan x is also positive for x in quadrant I, so you take the positive root again. You're left with

\tan\dfrac x2=\dfrac15
4 0
3 years ago
What is a reciprocal?
prohojiy [21]
<span>a mathematical expression or function so related to another that their product is one; the quantity obtained by dividing the number one by a given quantity.
</span>
7 0
3 years ago
Read 2 more answers
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