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8_murik_8 [283]
3 years ago
10

Terri owns a computer repair shop. Her revenue at the end of last month was $8,000. What is Terri's Run Rate?

Mathematics
1 answer:
Ilia_Sergeevich [38]3 years ago
6 0

Based on the information given Terri's Run Rate is $96,000.

<h3>Run rate</h3>

Using this formula

Run rate=Revenue for the Period × Number of months in a year

Where:

Revenue for the Period =$8,000

Number of months in a year=12 months

Let plug in the formula

Run rate=$8,000×12 months

Run rate=$96,000

Inconclusion Terri's Run Rate is $96,000.

Learn more about run rate here:brainly.com/question/16134508

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Answer:

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Step-by-step explanation:

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SA = 2(lw) + 2(wh) + 2(hl)

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Substitute the given values and multiply:

SA = 2(lw) + 2(wh) + 2(hl)

SA = 2(36)(10) + 2(10)(2) + 2(2)(36)

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Answer:

  • Part A: The price of fuel A is decreasing by 12% per month.

  • Part B: Fuel A recorded a greater percentage change in price over the previous month.

Explanation:

<u>Part A:</u>

The function     f(x)=2.27(0.88)^x     calculates the price of fuel A each month by multiplying the price of the month before by 0.88.

Month       price, f(x)

1                 2.27 (0.88) = 1.9976 ≈ 2.00

2                2.27(0.88)² = 1.59808 ≈ 1.60

3                2.27(0.88)³ = 1.46063 ≈ 1.46

Then, the price of fuel A is decreasing.

The percentage per month is (1 - 0.88) × 100 = 12%, i.e. the price decreasing by 12% per month.

<u>Part B.</u>

<u>Table:</u>

m       price, g(m)

1          3.44

2         3.30

3          3.17

4         3.04

To find if the function decreases with a constant ration divide each pair con consecutive prices:

  • ratio = 3.30 / 3. 44 = 0.959 ≈ 0.96
  • ratio = 3.17 / 3.30 = 0.960 ≈ 0.96
  • ratio = 3.04 / 3.17 = 0.959 ≈ 0.96

Thus, the price of fuel B is decreasing by (1 - 0.96) × 100 =4%.

Hence, the fuel A recorded a greater percentage change in price over the previous month.

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